anonymous
  • anonymous
A cone has a diameter of 6 centimeters and a height that is 3 times the diameter. Using 3.14 for pi, which of the following can be used to calculate the volume of the cone? one over three(3.14)(3cm)2(18cm) one over three(3.14)(6cm)2(18cm) one over three(3.14)(18cm)2(3cm) one over three(3.14)(18cm)2(6cm)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@geekfromthefutur
anonymous
  • anonymous
@Jack1
Jack1
  • Jack1
1 Attachment

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Jack1
  • Jack1
From Question: "A cone has a diameter of 6 centimeters" therefore Radius = half of diameter radius = 3 cm
Jack1
  • Jack1
From question: "and a height that is 3 times the diameter" h = 3D D = 6 therefore h = 18
Jack1
  • Jack1
so if Volume of a Cone = pi x r^2 x h x 1/3 \(\Large V = \pi \times r^2 \times h \times \frac13\)
Jack1
  • Jack1
so which answer do you thing it is @Moo_Moo17 ?
anonymous
  • anonymous
i think its A (:
Jack1
  • Jack1
yep, perfect!
anonymous
  • anonymous
oh ok i only have 3 more question ^-^ would it be ok if u could help me ??

Looking for something else?

Not the answer you are looking for? Search for more explanations.