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anonymous

  • one year ago

Can I get some help with a few questions?

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  1. zzr0ck3r
    • one year ago
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    ?

  2. anonymous
    • one year ago
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    One moment, need to screenshot!

  3. anonymous
    • one year ago
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  4. UnkleRhaukus
    • one year ago
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    two angles are supplementary, iff they add to 180°

  5. anonymous
    • one year ago
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    Okay..

  6. UnkleRhaukus
    • one year ago
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    iff \(\angle FEA\) is supplementary to \(\angle HGD\) \[\text m\angle FEA+\text m\angle HGD = 180°\]

  7. anonymous
    • one year ago
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    Wait.. I don't understand...

  8. UnkleRhaukus
    • one year ago
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    consider the first option, does it agree?

  9. anonymous
    • one year ago
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    Yes?..

  10. UnkleRhaukus
    • one year ago
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    What is it that you don't understand?

  11. anonymous
    • one year ago
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    Just the overall question. It's weird. It's not option A or B is what I'm getting so far, right?

  12. UnkleRhaukus
    • one year ago
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    (check carefully now) Does: \[\text m\angle FEA+\text m\angle HGD = 180°\] agree with option one?

  13. anonymous
    • one year ago
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    It.. it's not 180, I think..?

  14. UnkleRhaukus
    • one year ago
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    I suppose the first thing you have to realize is that any angle, can only have one supplement so iff ∠FEA is supplementary to ∠HGD then effectively A = C, B= D, E=G, F=H

  15. UnkleRhaukus
    • one year ago
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    there are only two angles to consider; the big one : ∠FEB = ∠HGD and the little angle : ∠FEA = ∠HGC

  16. UnkleRhaukus
    • one year ago
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    where any pair, of one big and one little angle, will always add to 180°,

  17. anonymous
    • one year ago
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    So A is not true, which makes it the right answer?

  18. UnkleRhaukus
    • one year ago
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    but why is A not true?

  19. anonymous
    • one year ago
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    Because the angles are too big, right?

  20. UnkleRhaukus
    • one year ago
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    yeah, big angle + big angle ≠ 180°

  21. anonymous
    • one year ago
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    Okay, I kinda get it...

  22. anonymous
    • one year ago
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    What about this problem?

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  23. UnkleRhaukus
    • one year ago
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    (unless all the angles were exactly 90°, which doesn't fit the diagram )

  24. UnkleRhaukus
    • one year ago
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    [if i remember correctly] alternate angles are equal, corresponding angles are equal, vertically opposite angles are equal , & co-interior angles are supplementary.

  25. UnkleRhaukus
    • one year ago
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    can you find the angles in the first option on the diagram?

  26. UnkleRhaukus
    • one year ago
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    |dw:1434794031396:dw|

  27. anonymous
    • one year ago
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    In the first one, they look equal to me.. unless I am not understanding this properly.

  28. UnkleRhaukus
    • one year ago
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    if they look equal (congruent), are they alternate angles? corresponding angles? vertically opposite angles ?

  29. anonymous
    • one year ago
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    Alternate, I think..

  30. UnkleRhaukus
    • one year ago
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    u can't see any angles alternate to angle EIA

  31. anonymous
    • one year ago
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    So it's the first option, yes?

  32. UnkleRhaukus
    • one year ago
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    |dw:1434794616346:dw|

  33. UnkleRhaukus
    • one year ago
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    |dw:1434794679515:dw|

  34. UnkleRhaukus
    • one year ago
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  35. anonymous
    • one year ago
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    Oh, so they're opposite angles?.. so they are congruent.

  36. UnkleRhaukus
    • one year ago
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    Yes!

  37. anonymous
    • one year ago
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    Then there's this... I was always bad at these in class.

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  38. UnkleRhaukus
    • one year ago
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    what is the difference between line 3, and line 4?

  39. anonymous
    • one year ago
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    They're adding segments together and asking if they're congruent.

  40. UnkleRhaukus
    • one year ago
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    3. AB + BC + CD = CD + DE + EF 4. AB + BC = DE + EF What has happened ?

  41. anonymous
    • one year ago
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    They're.. substituting I think?

  42. UnkleRhaukus
    • one year ago
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    what has been substituted for what?

  43. anonymous
    • one year ago
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    The concurrency, I think.

  44. anonymous
    • one year ago
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    *congruent

  45. UnkleRhaukus
    • one year ago
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    nope

  46. UnkleRhaukus
    • one year ago
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    3. AB + BC + CD = CD + DE + EF 4. AB + BC = DE + EF how are theses lines different ?

  47. anonymous
    • one year ago
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    Uh.. I have no legitimate clue.

  48. UnkleRhaukus
    • one year ago
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    read line 3. and then read line 4.

  49. anonymous
    • one year ago
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    It removed two of the segments, I see that much.. :/

  50. anonymous
    • one year ago
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    @TillLindemann no CD

  51. UnkleRhaukus
    • one year ago
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    yeas, CD has been taken away from both sides of the equation

  52. anonymous
    • one year ago
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    Okay.. so it's asking if they're still congruent without them, no?

  53. anonymous
    • one year ago
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    So would it not be D?..

  54. UnkleRhaukus
    • one year ago
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    The question is , what reason justifies us being able to take away some term that appears on both sides of the equation

  55. anonymous
    • one year ago
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    So D, yes? I'm so confused.

  56. UnkleRhaukus
    • one year ago
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    another word for take-away or minusing, is subtraction

  57. anonymous
    • one year ago
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    Wait. So.. It's C?

  58. UnkleRhaukus
    • one year ago
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    does that makes sense now?

  59. anonymous
    • one year ago
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    Yes, because they removed one of the segments, it makes it the Subtraction property, right?

  60. anonymous
    • one year ago
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    This is one of those ones where you have to do a bunch of weird nitpicking to get the correct answer...

  61. UnkleRhaukus
    • one year ago
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    Yes, the subtraction property of equality states that: if some expression is equal to some other expression, and both expressions have +some term, you can take away the +some term form both sides and the resulting expressions will still remain equal to one another A + c = c+ B (taking away c) A = B

  62. anonymous
    • one year ago
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  63. anonymous
    • one year ago
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    Not sure, but I think it's linear and angle BED...

  64. anonymous
    • one year ago
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    Er, not angle.. but.. you get what I'm trying to say.

  65. anonymous
    • one year ago
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  66. UnkleRhaukus
    • one year ago
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    what is the linear angle theorem?

  67. anonymous
    • one year ago
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    |dw:1434796331473:dw| This right?

  68. UnkleRhaukus
    • one year ago
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    that might be the linear angle theorem, but i don't see how it relates to this question

  69. UnkleRhaukus
    • one year ago
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    you got \(\angle AEC \cong \angle BED \) (by the vertical angle theorem) right

  70. UnkleRhaukus
    • one year ago
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    the linear angle theorem is not about congruence (equality), it is a about supplementary angles

  71. anonymous
    • one year ago
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    Okay, but?...

  72. UnkleRhaukus
    • one year ago
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    compare the two lines of this question

  73. anonymous
    • one year ago
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    Is it vertical?..

  74. UnkleRhaukus
    • one year ago
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    yer

  75. anonymous
    • one year ago
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    And still angle BED, right?

  76. UnkleRhaukus
    • one year ago
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    yep they are vertically opposite angles in each case

  77. anonymous
    • one year ago
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    This one is really long as well.

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  78. UnkleRhaukus
    • one year ago
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    what do you think

  79. anonymous
    • one year ago
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    Well, I've had this question multiple times before and I always get it wrong...

  80. anonymous
    • one year ago
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  81. anonymous
    • one year ago
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  82. anonymous
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  83. UnkleRhaukus
    • one year ago
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    i'm not going to tell you what the answer is

  84. anonymous
    • one year ago
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    I know that, but I haven't a single clue on how to find it..

  85. UnkleRhaukus
    • one year ago
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    Which parts of the closed passage do you not understand exactly?

  86. anonymous
    • one year ago
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    Well, this whole section really.

  87. UnkleRhaukus
    • one year ago
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    first line says some lines are parallel, some angles are equal. prove some other angle are supplementry

  88. anonymous
    • one year ago
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    Yes, I think the first answer to the big question is transitive..

  89. UnkleRhaukus
    • one year ago
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    i think that is right, what about the next one

  90. anonymous
    • one year ago
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    Vertical maybe...

  91. UnkleRhaukus
    • one year ago
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    vertical angles are congrunent (not supplementary )

  92. anonymous
    • one year ago
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    It's not linear, right?.. or is it?

  93. UnkleRhaukus
    • one year ago
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    Which do you think ?

  94. UnkleRhaukus
    • one year ago
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    |dw:1434798665055:dw|

  95. anonymous
    • one year ago
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    I think it's linear but I have no clue.. could be the congruent supplements one though.

  96. UnkleRhaukus
    • one year ago
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    the congruent supplements theorem involves three angles you have plenty of clues

  97. anonymous
    • one year ago
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    So then it is linear, no?

  98. UnkleRhaukus
    • one year ago
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    why not, eh?

  99. anonymous
    • one year ago
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    And I think the last one is substitution, because it's assuming, and substituting numbers into the whole thing.

  100. UnkleRhaukus
    • one year ago
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    Yep substitution is right

  101. anonymous
    • one year ago
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  102. anonymous
    • one year ago
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    I think it's the first option...

  103. UnkleRhaukus
    • one year ago
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    that doesn't prove the what you are trying to prove

  104. UnkleRhaukus
    • one year ago
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    the last line of the proof should say something about what you are trying to prove

  105. anonymous
    • one year ago
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    The congruent supplement one, yeah.. I think that's the right answer.

  106. UnkleRhaukus
    • one year ago
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    In this question you are trying to prove that \(\angle 3\cong \angle 6\), ... you have \(\angle 3\cong \angle 7\), ... you need something\(\cong\angle 6\), ...

  107. anonymous
    • one year ago
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    Now I feel like it's more option D...

  108. anonymous
    • one year ago
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    B?...

  109. UnkleRhaukus
    • one year ago
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    stop guessing

  110. anonymous
    • one year ago
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    Well I don't understand.

  111. UnkleRhaukus
    • one year ago
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    \[\angle 3\cong \cdots\cong\angle6, ...\]

  112. anonymous
    • one year ago
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    That doesn't help me.

  113. anonymous
    • one year ago
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    Because there is no option with 3 and 6 in it at the same time.

  114. UnkleRhaukus
    • one year ago
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    you have \[\angle 3\cong \angle 7, ...\] you need \[\angle 7\cong\angle6, ...\]

  115. anonymous
    • one year ago
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    So it'd D.

  116. UnkleRhaukus
    • one year ago
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    Um, yes it is.

  117. anonymous
    • one year ago
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    Thank you. That's all I needed for now. Thanks so much for helping.

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