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anonymous

  • one year ago

Consider a random variable X that takes on the values 0, 1, 2, 3. We specify the function f(x) = -2 + x. Is f(x) a probability mass function?

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  1. anonymous
    • one year ago
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    Is it No because the first and second Kolmogorov axioms are being violated?

  2. sdfgsdfgs
    • one year ago
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    no, because f(1)=-1 n first axiom requires P(x) >=0

  3. anonymous
    • one year ago
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    SO, then it is No because the probabilities do not sum to 1? I just realised the Axiom thing.

  4. sdfgsdfgs
    • one year ago
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    do not sum to 1 will be the second axiom but f(x) does not even satisfy the first of being non-negative.

  5. anonymous
    • one year ago
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    Ok thank you so much!

  6. sdfgsdfgs
    • one year ago
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    welcome

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