• anonymous
If the derivative of ​f[x_] = (x^2 - 2 Log[x]) ​f'[x_] = (2x - 2/x) Then why is the derivative of ​f[x_] = (x^2 - 2 Log[x])/2 ​f'[x_] = (2x - 2/x)/2 What is the principle that allows the /2 which appears to be some kind of constant to remain in the derivative ?
Mathematics
• Stacey Warren - Expert brainly.com
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SOLVED
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