If the derivative of
f[x_] = (x^2 - 2 Log[x])
f'[x_] = (2x - 2/x)
Then why is the derivative of
f[x_] = (x^2 - 2 Log[x])/2
f'[x_] = (2x - 2/x)/2
What is the principle that allows the /2 which appears to be some kind of constant to remain in the derivative ?

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because derative is a linear operator

constants can be factored out of the derivative

wow this guy must be rich to do a QH question

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