plz help

- anonymous

plz help

- katieb

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

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- anonymous

##### 1 Attachment

- anonymous

its on the doc.

- anonymous

1. B
i would love to help.. but i dont know the rest
@Michele_Laino help

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## More answers

- anonymous

ok thx

- anonymous

http://assets.openstudy.com/updates/attachments/55857509e4b091b59af14393-foxycrew-1434809630481-1213.doc

- Michele_Laino

yes! I confirm, the answer is:
\[\frac{1}{{\sin \theta }} = \csc \theta \]

- anonymous

help her for the rest

- anonymous

im a boy

- Michele_Laino

hint:
when an object is moving, its position is a function of...?

- Michele_Laino

- anonymous

sorry @foxycrew

- anonymous

speed

- Michele_Laino

I think, it is a function of time, am I right?

- Michele_Laino

- anonymous

your on 2 right??

- Michele_Laino

yes!

- anonymous

is it a

- Michele_Laino

I think option D, since frequency is the inverse of time

- anonymous

ok thx

- Michele_Laino

ok! Let's go to question #3

- anonymous

ok

- Michele_Laino

hint:
we have this relationship:
|dw:1434810747850:dw|
\[\Large a = c\cos \beta \]

- Michele_Laino

so what is the right option?

- anonymous

um i say C or B

- Michele_Laino

hint:
from the preceding formula, we can write:
\[\Large \cos \beta = \frac{a}{c}\]
there a is the adjacent side with respect to angle \beta, whereas c is the hypotenuse

- anonymous

im so lost

- Michele_Laino

a is the adjacent side with respect to \beta, right?

- Michele_Laino

and c is the hypotenuse

- anonymous

idk im on this to help me

- anonymous

http://www.themathpage.com/atrig/trigonometry-of-right-triangles.htm

- Michele_Laino

so we can write:
\[\Large \cos \beta = \frac{a}{c} = \frac{{{\text{adjacent side}}}}{{{\text{hypotenuse}}}}\]

- anonymous

so its B.

- Michele_Laino

|dw:1434811375224:dw|

- Michele_Laino

that's right! It is option B

- anonymous

to 4

- Michele_Laino

ok! now let's go on question #4

- anonymous

i think 4 is d

- Michele_Laino

that's right!

- anonymous

ya :D

- Michele_Laino

:)
now let's go on question #5

- anonymous

ok

- anonymous

90 to 180 ??

- Michele_Laino

here we have to consider the graph of the function sin(x), like this:
|dw:1434811615558:dw|

- Michele_Laino

where the function sin(x) is an increasing function?

- anonymous

yes

- Michele_Laino

from 90 to 180, I think no, since we have:
|dw:1434811790842:dw|

- Michele_Laino

so, what is the right option?

- anonymous

D.

- Michele_Laino

are you sure? please look at my last drawing

- Michele_Laino

hint:
|dw:1434811920630:dw|

- anonymous

um 0 to 90 ??

- Michele_Laino

yes! that's right!

- anonymous

thx you btw

- Michele_Laino

so, it is option B

- Michele_Laino

now, let's go on question #6

- anonymous

6. How many complete revolutions are needed to draw the angle 725°?

- Michele_Laino

yes!

- anonymous

it 2 right??

- Michele_Laino

that's right! since we can write:
\[\Large 725 = 2 \times 360 + 5\]

- Michele_Laino

next question #7

- anonymous

7. To use the law of sines, which of the following statements must be true?
A. All three side lengths must be known.
B. At least one side length and opposite angle pair must be known.
C. At least two angles must be known.
D. The triangle must be a right triangle.

- Michele_Laino

hint:
the law of sines is:
|dw:1434812267441:dw|
\[\frac{a}{{\sin \alpha }} = \frac{b}{{\sin \beta }}\]

- Michele_Laino

now if I want to compute the value of the side a, I have to use this formula:
\[\Large a = b\frac{{\sin \alpha }}{{\sin \beta }}\]

- Michele_Laino

so I have to know the angle \alpha, the angle \beta, and the length of the side b

- anonymous

um is it B. At least one side length and opposite angle pair must be known.

- Michele_Laino

yes! correct!

- Michele_Laino

now let's go on question #8

- anonymous

8. An angle in a right triangle is identified as θ. If the tangent of θ equals one, what must be true about the triangle side lengths?
A. The side opposite to theta is longer than the adjacent side.
B. The side adjacent to theta is half the length of the hypotenuse.
C. The sides opposite and adjacent to theta are the same length.
D. The side adjacent to theta is longer than the adjacent side.

- anonymous

i dont get this one its hard

- Michele_Laino

hint:
|dw:1434812588863:dw|

- Michele_Laino

here we can write:
\[\Large a = b\tan \theta = b \times 1 = b\]
so what can you conclude?

- anonymous

i say D.

- Michele_Laino

we have a=b
a is the side opposite to theta, whereas b is the side adjacent to theta

- anonymous

hmm

- Michele_Laino

so, what is the right option?

- anonymous

a.

- Michele_Laino

are you sure?
a and b have the same length

- anonymous

true

- Michele_Laino

so, what is the right option?

- anonymous

is adjacent the big one ??

- Michele_Laino

no, since they have the same length

- anonymous

so opposite ??

- Michele_Laino

namely?

- anonymous

C. The sides opposite and adjacent to theta are the same length.

- Michele_Laino

that's right! correct!

- anonymous

9. _______ angles are used to relate the values returned by inverse trigonometric functions to angles larger than 90°.
A. Obtuse
B. Acute
C. Right
D. Complementary

- anonymous

afk i have to eat sory

- Michele_Laino

ok! Please wait I have to go out, I will return as soon as possible

- anonymous

ok back

- Michele_Laino

here I am @foxycrew

- anonymous

ok

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