anonymous
  • anonymous
plz help
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
its on the doc.
anonymous
  • anonymous
1. B i would love to help.. but i dont know the rest @Michele_Laino help

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anonymous
  • anonymous
ok thx
anonymous
  • anonymous
http://assets.openstudy.com/updates/attachments/55857509e4b091b59af14393-foxycrew-1434809630481-1213.doc
Michele_Laino
  • Michele_Laino
yes! I confirm, the answer is: \[\frac{1}{{\sin \theta }} = \csc \theta \]
anonymous
  • anonymous
help her for the rest
anonymous
  • anonymous
im a boy
Michele_Laino
  • Michele_Laino
hint: when an object is moving, its position is a function of...?
Michele_Laino
  • Michele_Laino
anonymous
  • anonymous
sorry @foxycrew
anonymous
  • anonymous
speed
Michele_Laino
  • Michele_Laino
I think, it is a function of time, am I right?
Michele_Laino
  • Michele_Laino
anonymous
  • anonymous
your on 2 right??
Michele_Laino
  • Michele_Laino
yes!
anonymous
  • anonymous
is it a
Michele_Laino
  • Michele_Laino
I think option D, since frequency is the inverse of time
anonymous
  • anonymous
ok thx
Michele_Laino
  • Michele_Laino
ok! Let's go to question #3
anonymous
  • anonymous
ok
Michele_Laino
  • Michele_Laino
hint: we have this relationship: |dw:1434810747850:dw| \[\Large a = c\cos \beta \]
Michele_Laino
  • Michele_Laino
so what is the right option?
anonymous
  • anonymous
um i say C or B
Michele_Laino
  • Michele_Laino
hint: from the preceding formula, we can write: \[\Large \cos \beta = \frac{a}{c}\] there a is the adjacent side with respect to angle \beta, whereas c is the hypotenuse
anonymous
  • anonymous
im so lost
Michele_Laino
  • Michele_Laino
a is the adjacent side with respect to \beta, right?
Michele_Laino
  • Michele_Laino
and c is the hypotenuse
anonymous
  • anonymous
idk im on this to help me
anonymous
  • anonymous
http://www.themathpage.com/atrig/trigonometry-of-right-triangles.htm
Michele_Laino
  • Michele_Laino
so we can write: \[\Large \cos \beta = \frac{a}{c} = \frac{{{\text{adjacent side}}}}{{{\text{hypotenuse}}}}\]
anonymous
  • anonymous
so its B.
Michele_Laino
  • Michele_Laino
|dw:1434811375224:dw|
Michele_Laino
  • Michele_Laino
that's right! It is option B
anonymous
  • anonymous
to 4
Michele_Laino
  • Michele_Laino
ok! now let's go on question #4
anonymous
  • anonymous
i think 4 is d
Michele_Laino
  • Michele_Laino
that's right!
anonymous
  • anonymous
ya :D
Michele_Laino
  • Michele_Laino
:) now let's go on question #5
anonymous
  • anonymous
ok
anonymous
  • anonymous
90 to 180 ??
Michele_Laino
  • Michele_Laino
here we have to consider the graph of the function sin(x), like this: |dw:1434811615558:dw|
Michele_Laino
  • Michele_Laino
where the function sin(x) is an increasing function?
anonymous
  • anonymous
yes
Michele_Laino
  • Michele_Laino
from 90 to 180, I think no, since we have: |dw:1434811790842:dw|
Michele_Laino
  • Michele_Laino
so, what is the right option?
anonymous
  • anonymous
D.
Michele_Laino
  • Michele_Laino
are you sure? please look at my last drawing
Michele_Laino
  • Michele_Laino
hint: |dw:1434811920630:dw|
anonymous
  • anonymous
um 0 to 90 ??
Michele_Laino
  • Michele_Laino
yes! that's right!
anonymous
  • anonymous
thx you btw
Michele_Laino
  • Michele_Laino
so, it is option B
Michele_Laino
  • Michele_Laino
now, let's go on question #6
anonymous
  • anonymous
6. How many complete revolutions are needed to draw the angle 725°?
Michele_Laino
  • Michele_Laino
yes!
anonymous
  • anonymous
it 2 right??
Michele_Laino
  • Michele_Laino
that's right! since we can write: \[\Large 725 = 2 \times 360 + 5\]
Michele_Laino
  • Michele_Laino
next question #7
anonymous
  • anonymous
7. To use the law of sines, which of the following statements must be true? A. All three side lengths must be known. B. At least one side length and opposite angle pair must be known. C. At least two angles must be known. D. The triangle must be a right triangle.
Michele_Laino
  • Michele_Laino
hint: the law of sines is: |dw:1434812267441:dw| \[\frac{a}{{\sin \alpha }} = \frac{b}{{\sin \beta }}\]
Michele_Laino
  • Michele_Laino
now if I want to compute the value of the side a, I have to use this formula: \[\Large a = b\frac{{\sin \alpha }}{{\sin \beta }}\]
Michele_Laino
  • Michele_Laino
so I have to know the angle \alpha, the angle \beta, and the length of the side b
anonymous
  • anonymous
um is it B. At least one side length and opposite angle pair must be known.
Michele_Laino
  • Michele_Laino
yes! correct!
Michele_Laino
  • Michele_Laino
now let's go on question #8
anonymous
  • anonymous
8. An angle in a right triangle is identified as θ. If the tangent of θ equals one, what must be true about the triangle side lengths? A. The side opposite to theta is longer than the adjacent side. B. The side adjacent to theta is half the length of the hypotenuse. C. The sides opposite and adjacent to theta are the same length. D. The side adjacent to theta is longer than the adjacent side.
anonymous
  • anonymous
i dont get this one its hard
Michele_Laino
  • Michele_Laino
hint: |dw:1434812588863:dw|
Michele_Laino
  • Michele_Laino
here we can write: \[\Large a = b\tan \theta = b \times 1 = b\] so what can you conclude?
anonymous
  • anonymous
i say D.
Michele_Laino
  • Michele_Laino
we have a=b a is the side opposite to theta, whereas b is the side adjacent to theta
anonymous
  • anonymous
hmm
Michele_Laino
  • Michele_Laino
so, what is the right option?
anonymous
  • anonymous
a.
Michele_Laino
  • Michele_Laino
are you sure? a and b have the same length
anonymous
  • anonymous
true
Michele_Laino
  • Michele_Laino
so, what is the right option?
anonymous
  • anonymous
is adjacent the big one ??
Michele_Laino
  • Michele_Laino
no, since they have the same length
anonymous
  • anonymous
so opposite ??
Michele_Laino
  • Michele_Laino
namely?
anonymous
  • anonymous
C. The sides opposite and adjacent to theta are the same length.
Michele_Laino
  • Michele_Laino
that's right! correct!
anonymous
  • anonymous
9. _______ angles are used to relate the values returned by inverse trigonometric functions to angles larger than 90°. A. Obtuse B. Acute C. Right D. Complementary
anonymous
  • anonymous
afk i have to eat sory
Michele_Laino
  • Michele_Laino
ok! Please wait I have to go out, I will return as soon as possible
anonymous
  • anonymous
ok back
Michele_Laino
  • Michele_Laino
here I am @foxycrew
anonymous
  • anonymous
ok

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