anonymous
  • anonymous
Trig Sine and Cosine Law Am I correct? Please do not give answer but guide me. Thank you. Ok, I have a triangle with A= 60 degrees and two sides which are b = 12 and c = 17 Ok, this to me is a Side Angle Side problem SAS, which requires the Cosine Law. Ok to solve for \( a^2 \) we would use \( a^2 = b^2+c^2 -2\times b \times c \times cos A \) which would be \( a^2 = 12^2+17^2 -2\times 12 \times 17 \times cos 60 \) which will equal \( a = \sqrt{229}\) Ok, I have more to come but is that correct so far???
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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AbdullahM
  • AbdullahM
Splendid work so far!
AbdullahM
  • AbdullahM
You are on the correct path :) Now we have to use Law of Sines to calculate the rest.
anonymous
  • anonymous
Ok now when I use \( cos B = \frac{\sqrt{229}^2+17^2}{2\times \sqrt{229}^2 \times 17} \) I get an error on my calculator....

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More answers

anonymous
  • anonymous
Why can't I find B like the following
anonymous
  • anonymous
Do we have to use Sine Law to find the rest. Why can't we use Cosine Law like the above?? My calculator errors out.
AbdullahM
  • AbdullahM
Using the Sin Law would be more easier :)
Loser66
  • Loser66
You apply cos b formula wrong
anonymous
  • anonymous
But Cosine should work correct?but my two calculators give errors
Loser66
  • Loser66
\(b^2 = a^2+c^2 -2ac cosb\\2ac cosb= a^2+c^2 -b^2\\cosb=\dfrac{a^2+c^2-b^2}{2ac}\)
anonymous
  • anonymous
Ah crap Loser66 you are right lol I forgot the -b^2 Man I thought I was losing my mind. I was like it should work LOL
anonymous
  • anonymous
Thanks to you all.
anonymous
  • anonymous
Still getting an error. Grrrrr lol
Loser66
  • Loser66
why? what do you hit on your calculator? , You need \(\angle b\) right?
anonymous
  • anonymous
Going to try my Ti nspire cx Still getting error on my Casio fx 115
Loser66
  • Loser66
My calculator said that b is \(\approx 41^0\)
anonymous
  • anonymous
Crap, I see where I made my mistake. I need to slow down. I hite times instead of plus
anonymous
  • anonymous
I got 43.37 degreess
Loser66
  • Loser66
hihihi... now, do it together: a^2 +c^2 -b^2 = 299 +17^2 -12^2 =444 ok?
AbdullahM
  • AbdullahM
I got 43.47 also
Loser66
  • Loser66
now divided by (2*17*sqrt (299) , we get 0.7552112641 ok?
anonymous
  • anonymous
Cool, thanks Loser66 and AbdullahM, Sending you both 5 owlbucks. Thanks for the help
anonymous
  • anonymous
I got it from here.
AbdullahM
  • AbdullahM
Anytime :))
Loser66
  • Loser66
now hit "2nd + cos^-1" then type 0.7552112641 it gives us 40.97463023
Loser66
  • Loser66
hihihi... that's what my calculator said.
AbdullahM
  • AbdullahM
Just to make sure, we can plug it into a calculator.
AbdullahM
  • AbdullahM
http://www.mathwarehouse.com/triangle-calculator/online.php?&sb=12&sc=17&aa=60#triangleAppData
Loser66
  • Loser66
sorry for correcting you again \(a=\sqrt{299}= 17.29\) not 15.13.. as you stated
AbdullahM
  • AbdullahM
Her number is \(\bf 229\) not 299.
Loser66
  • Loser66
oh yeah. my bad. I was wrong.

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