anonymous
  • anonymous
solve the equation using quadratic formula. 2x (sqaured) +13x=0
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
can some one please help ,e i dont get quadratic functions
pooja195
  • pooja195
Find a GCF first do you see any?
anonymous
  • anonymous
13?

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More answers

AbdullahM
  • AbdullahM
It says to solve by using the Quadratic Formula... What is the Quadratic Formula?
anonymous
  • anonymous
"ax2 + bx + c = 0"
pooja195
  • pooja195
Thats standered form
AbdullahM
  • AbdullahM
|dw:1434816541031:dw|
anonymous
  • anonymous
yeah but for this question thers no c
pooja195
  • pooja195
so that would be 0 then :)
anonymous
  • anonymous
but dont u have tp plug in the numbers? or is it when theres no c then the answer is equivalent to 0?
pooja195
  • pooja195
Name your abc values
anonymous
  • anonymous
a=2 b=13
pooja195
  • pooja195
\[\huge~\rm~ax^2+bx+c=0\] \[\huge~\rm~2x^2+13x+0=0\]
pooja195
  • pooja195
Now name the abc values
anonymous
  • anonymous
a=2 b=13 c=0?
AbdullahM
  • AbdullahM
Great job so far :)
pooja195
  • pooja195
yes! :) \[\huge~\rm~~x=\frac{ -(13)~\pm \sqrt{(13)^2-4(2)(0)} }{ 2(2)}\]
anonymous
  • anonymous
\[so.... x= -13 \pm \sqrt{169}\]
anonymous
  • anonymous
and then i would subtract 8?
anonymous
  • anonymous
i dont understnd now...
pooja195
  • pooja195
\[\huge~\rm~~x=\frac{ -13~\pm \sqrt{169~x~1} }{ 4}\] \[\huge~\rm~~x=\frac{ -13~\pm \sqrt{169} }{ 4}\] Whats the square root of 169?
anonymous
  • anonymous
13
anonymous
  • anonymous
right?
pooja195
  • pooja195
\[\huge~\rm~~x=\frac{ -13~\pm~13 \sqrt{1} }{ 4}\] now set up two equations and solve \[\huge~\rm~~x=\frac{ -13~+~13 \sqrt{1} }{ 4}\] \[\huge~\rm~~x=\frac{ -13~-~13 \sqrt{1} }{ 4}\]
anonymous
  • anonymous
so it would be -13/2 and 0?
anonymous
  • anonymous
those are my two answers correct?
anonymous
  • anonymous
so would i do the same thing for 6x (sqaured) +2x=4?
pooja195
  • pooja195
You would subtract the 4 \[\huge~\rm~6x^2+2x-4=0\] and go from that

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