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anonymous
 one year ago
10. The trig functions cosine and secant are related through a(n) _______ trig identity.
A. Pythagorean
B. reciprocal
C. inverse
D. quotient
anonymous
 one year ago
10. The trig functions cosine and secant are related through a(n) _______ trig identity. A. Pythagorean B. reciprocal C. inverse D. quotient

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AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1\(\sf\Large sec(x)=\frac{1}{cos(x)}\) What do you think it is?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@AbdullahM can you help me out

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1No; Phytagorean trig identity is based off of \(\sf a^2+b^2=c^2\) And a Phytagorean Trig identity example is: \(\sf sin^2(x)+cos^2(x)=1\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so can you help me @AbdullahM

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1What is cos to sec? Is it the inverse? reciprocal? quotient?

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1If anything else, you can seach up inverse trig identity reciprocal trig identity and see if \(\sf\Large sec(x)=\frac{1}{cos(x)}\) comes under it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0CAN YOU HELP ME @AbdullahM !!!!!!!!!!!!!!!!!!!!!!!!!!!!!1

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1Tag me in your post please.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0who are you talking to

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the question is the same as @coolswag and the answers are the same

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so......................................................................................................................................... did you find the answer @AbdullahM

AbdullahM
 one year ago
Best ResponseYou've already chosen the best response.1Please go to the other post where I'm helping :)
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