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please help me!
This is just like the other one, except now you have to use the graph to pick out the values. What is the vertex?
yes. and the roots?
i'm not sure what the roots are...
the roots are where the graph crosses the x-axis. For example|dw:1434816829118:dw|
What is the x where your parabola crosses?
1 and 5?
yes. Now try plugging the roots into the equation. Remember the form is \[y = a(x-p)(x-q)\] Where p and q are the roots
not quite. We're not using the vertex yet or plugging in for x and y... yet. We have to set up the equation first. The root are 1 and 5, so plug in 1 and 5 for p and q to get y = a(x - 1)(x - 5) *It doesn't matter which is p and which is q*
NOW you plug in the vertex to solve for a
oh, okay. let me try.
yes, now solve it for a
thanks. hold on.
yes. can I see your final equation to make sure you got the format right?
The a, p, and q are constants that we used properties to find. They are the same for every point on the parabola. The x and y are variables and change for every point, so we need them to stay. So the equation is y = ½(x -1)(x - 5)
so i solve this equation?
no, that's the answer
thanks again man, this helped.