anonymous
  • anonymous
Getting another Calculator Error Cosine Law Trig Here is the problem A = 103 degrees Sides are b =31 c=52 Equation \( a^2 = 31^2+52^2-2\times 31 \times 52 \) = a = 66.2589 \( \large \cos B = \frac{66.25^2 +52^2-31^2}{2\times 66.25\times52} \) Am I right so far?? Do you get an error?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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AbdullahM
  • AbdullahM
Where is cos(A) in the equation?
AbdullahM
  • AbdullahM
\( \sf a^2 = 31^2+52^2-2\times 31 \times 52 cos(103)\) = 66.2589
AbdullahM
  • AbdullahM
Oh nevermind, you forgot to put cos(103) but you arrived at the correct a value.

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anonymous
  • anonymous
Did I forget to square that??
AbdullahM
  • AbdullahM
\( \sf a^2 = 31^2+52^2-2\times 31 \times 52 cos(103)\) then a=66.2589 not a^2, my bad.
anonymous
  • anonymous
Ok cool. Do you get an error on your cal??
anonymous
  • anonymous
\( \huge B =\cos^{-1}( \frac{66.25^2 +52^2-31^2}{2\times 66.25\times52} )\) I get an error
anonymous
  • anonymous
Crap it worked this time........ I got 27.12
AbdullahM
  • AbdullahM
So now we have: A= 103 degrees a = 66.26 b=31 c=52 Using sin laws \(\sf\Large \frac{sin103}{66.26} =\frac{sinB}{31}=\frac{sinC}{52}\) So we want to solve for \(\sf B\). \(\sf\Large \frac{sin103}{66.26} =\frac{sinB}{31}\) Cross multiply \(\sf\Large sin(103) \times 31 = Sin B\times 66.26\)
AbdullahM
  • AbdullahM
Yes, 27.12 is the correct value for B :)
anonymous
  • anonymous
That is strange..... I did not do anything . I just hit my back button to bring it up again and then hit enter and it gave me the answer. LOL
anonymous
  • anonymous
Wierd.... Stuff is going to drive me batty
AbdullahM
  • AbdullahM
Calculators are evil lol
anonymous
  • anonymous
Thanks for the help. :-)
AbdullahM
  • AbdullahM
Anytime :)
AbdullahM
  • AbdullahM
Once you get the hang of the questions, it will become more easier xD

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