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anonymous

  • one year ago

Using the following triangle, what is the secant of angle B?

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  1. anonymous
    • one year ago
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    answer choices are Sec B= c/b Sec B= a/c Sec B= b/c Sec B= c/a

  2. anonymous
    • one year ago
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    someone please help

  3. AbdullahM
    • one year ago
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    Hint: \(\sf\Large sec(B)= \frac{1}{cos(B)}\)

  4. anonymous
    • one year ago
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    i really don't know how to do this...

  5. AbdullahM
    • one year ago
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    |dw:1434820417301:dw|

  6. anonymous
    • one year ago
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    i think i kind of see what you're showing me...

  7. AbdullahM
    • one year ago
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    Find \(\sf cos(B)\) and then do the reciprocal of that to find out what \(\sf sec(B) \) is. :)

  8. anonymous
    • one year ago
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    so it's Sec B b/c?

  9. AbdullahM
    • one year ago
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    No... What is \(\sf cos(B)\) first?

  10. anonymous
    • one year ago
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    cos(B) is adj/hyp

  11. acxbox22
    • one year ago
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    SEC(B)=hypotenuse/adjacent which is the same as the reciprocal of COS(B)

  12. AbdullahM
    • one year ago
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    ^ exactly.

  13. AbdullahM
    • one year ago
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    So what side is adjacent to angle B?

  14. anonymous
    • one year ago
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    the opposite?

  15. AbdullahM
    • one year ago
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    |dw:1434821019903:dw|

  16. AbdullahM
    • one year ago
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    The adjacent side.

  17. anonymous
    • one year ago
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    oh. sorry ....

  18. anonymous
    • one year ago
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    so what's the annswer?

  19. AbdullahM
    • one year ago
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    |dw:1434821272236:dw| What is the adjacent side to angle B?

  20. anonymous
    • one year ago
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    b

  21. anonymous
    • one year ago
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    the one between A and C

  22. AbdullahM
    • one year ago
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    That is the side opposite to it, not adjacent.

  23. anonymous
    • one year ago
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    a?

  24. AbdullahM
    • one year ago
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    correct, and what is the hypotenuse?

  25. AbdullahM
    • one year ago
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    Sec(B)=hypotenuse/adjacent so adj=a \(\sf\Large Sec(B)=\frac{Hypotenuse}{a}\) Which answer choice has a in the denominator?

  26. anonymous
    • one year ago
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    the denominator?

  27. AbdullahM
    • one year ago
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    |dw:1434821783694:dw|

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