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http://www.regentsprep.org/regents/math/algtrig/atc1/circlelesson.htm

sorry i gtg ^ that links explains what you have to do

awh man :c

its ok i'll try to figure it out thanks tho :)

@pooja195 help me please :((

i'll try, sorry im not good at this

im back

we know that:\[(x+a)^2=x^2+2ax+a^2\]

and we want to get:\[x^2+2x\]

can you see what value of \(a\) we need to pick?

what do u mean @asnaseer

thanks though :)) @acxbox22

is it 1?

correct! :)

phew than God i felt so stupid lol

so we know that:\[(x+1)^2=x^2+2x+1\]agreed so far?

yes :)

i.e. we know:\[(x+1)^2=x^2+2x+1\]\[\therefore (x+1)^2-1=x^2+2x+1-1=x^2+2x\]

ohhh so now we're left with \[x^2+2x\] ?

exactly

yes :)

\[(x+1)^2-1+y^2+4y=20\]\[\therefore (x+1)^2-1+y^2+4y+1=20+1\]\[(x+1)^2+y^2+4y=21\]following so far?

yes :)

2 :3

perfect! :)

yes :D

agreed c:

agreed?

i get it now!! so the center will be (-1,-2) and the radius will be 5? :D

OMG THANK YOU SO MUCHHH!!!! you're a life saver, i really appreciate your help :))) <3

ok, bye for now - take care my friend :)

thx and you too :)