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anonymous
 one year ago
The length of a rectangle is 5 more than 3 times its width. The perimeter of the rectangle is 58 inches. What is the length of the rectangle?
anonymous
 one year ago
The length of a rectangle is 5 more than 3 times its width. The perimeter of the rectangle is 58 inches. What is the length of the rectangle?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0A) 23 in. B) 29 in. C) 32 in. D) 35 in.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0L = Length W = Width P = Perimetre P = 2(L + W) L = 3W + 5 L + W = 41 3W + 5 + W = 41 4W = 36 [ W = 9 inches ] L = 3W + 5 L = 3(9) + 5 [ L = 32 inches ] Hope this helps

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0your welcome I really do hope u get it right

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0@LesTwins It would be nice to do a check when solving system of equations For example, with the solution W=9, L=32, Perimeter= 2(W+L) = 2(9+32) = 82 \(\ne\) 58 as given in the question. So a review of the solution is necessary.

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0Also, most of the time, we can do a substitution in situ to avoid a system of equations of two unknowns, for example: Given: Perimeter = 58 inches and Length = 3*width +5 inches. Let W=width, L=length, then L=3W+5 Perimeter = 2(W+L)= 2(W+3W+5) = 58 Divide by two on both sides 4W+5=29 4W=24 W=6 and L=3W+5 = 23 Check: Perimeter = 2(W+L)=2(6+23)=2(29)=58 inches as given. Answer: Width = 6 inches, Length = 23 inches.
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