anonymous
  • anonymous
The length of a rectangle is four times its width. If the perimeter is at most 130 centimeters, what is the greatest possible value for the width? A. 13 cm B. 21.7 cm C. 26 cm D. 52 cm
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Godlovesme
  • Godlovesme
\[P = 2(l+w) \] in this case the length is \(4~times~its~width\) which means \[length = 4*width = 4w\]
Godlovesme
  • Godlovesme
@MonkeyQueen got that part?
Godlovesme
  • Godlovesme
@MonkeyQueen u there?

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nincompoop
  • nincompoop
let: l for length and w for width conditions: length is 4 times the width, so rewrite it as \(l = 4w \) given: Perimeter, \(P_{rectangle} = 130~cm\) the formula for perimeter of a rectangle is the sum of its sides \(P_{rectangle} = 2l + 2w \) apply the condition where \(l = 4w \) rewrite your equation so \(l\) will reflect the condition \(P_{rectangle} = 2(4w) + 2w \)
nincompoop
  • nincompoop
take it from where I left off and solve the problem :)
anonymous
  • anonymous
Thank you, I got it :)

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