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anonymous
 one year ago
The length of a rectangle is four times its width. If the perimeter is at most 130 centimeters, what is the greatest possible value for the width?
A.
13 cm
B.
21.7 cm
C.
26 cm
D.
52 cm
anonymous
 one year ago
The length of a rectangle is four times its width. If the perimeter is at most 130 centimeters, what is the greatest possible value for the width? A. 13 cm B. 21.7 cm C. 26 cm D. 52 cm

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Godlovesme
 one year ago
Best ResponseYou've already chosen the best response.1\[P = 2(l+w) \] in this case the length is \(4~times~its~width\) which means \[length = 4*width = 4w\]

Godlovesme
 one year ago
Best ResponseYou've already chosen the best response.1@MonkeyQueen got that part?

Godlovesme
 one year ago
Best ResponseYou've already chosen the best response.1@MonkeyQueen u there?

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.2let: l for length and w for width conditions: length is 4 times the width, so rewrite it as \(l = 4w \) given: Perimeter, \(P_{rectangle} = 130~cm\) the formula for perimeter of a rectangle is the sum of its sides \(P_{rectangle} = 2l + 2w \) apply the condition where \(l = 4w \) rewrite your equation so \(l\) will reflect the condition \(P_{rectangle} = 2(4w) + 2w \)

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.2take it from where I left off and solve the problem :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you, I got it :)
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