## anonymous one year ago This cannot be solved can it? I need to find c. Drawing is coming up.

1. anonymous

|dw:1434826619845:dw| This is not a 90 degree triangle

2. anonymous

60 is 60 degree angle

3. anonymous

its not a right triangle are you sure?

4. anonymous

Yes, I thought it might of been but I asked my instructor and he said no. So I am assume it cannot be solved.

5. anonymous

It can be solved but with some high tech trig stuffs. So I would just go with not able to be solved :)

6. anonymous

Hummm I might of seen something

7. anonymous

I am doing high tech trig stuff. Well I am working with Sine and Cosine laws.

8. anonymous

Yes

9. anonymous

If it was a right triangle you could use tangent and figure it out easily but im not sure since its not a right triangle

10. anonymous

sorry ment cosine

11. anonymous

I think I am on to something. BRB I might of solved it.

12. anonymous

ok after could you help me on my problem? I would appreciate it im stuck lol

13. anonymous

Yeah I solved it. I have to get b first. Then I can solve. |dw:1434827560899:dw| b = $$\tan60 = \frac{3}{b}$$ After I find b I can solve with Sine Law. :-) I got it :-)

14. anonymous

15. anonymous

i did @nicky on it check you inbox for the notifications to take you to the page

16. hartnn

To use sine/cosine law, you need any 3 out of 6 information (3 sides, 3 angles) here you're given only 2 of those info....

17. AbdullahM

Interesting question... Did they give you any information? Or all they gave you was that triangle with 2 pieces out of the 6. (3 angles, and 3 sides.)

18. anonymous

@AbdullahM did you see my last post where I stated I got it? I had to solve for b first and then I could use Sine Law. After I have b I have two sides and an angle which will allow me to solve the rest using Sine Law. tan 60 = 3/b which is 3 / tan 60 = b :-) I had to think about it for a minute but I got it.

19. AbdullahM

Oh, so this refers to the previous post xD So, we were given in the previous post: A = 103 degrees b =31 c=52 and we got in the previous post: a=66.26 B=27.12 degrees So, we can use either Law of Sines or Law of cosines... $$\sf\Large \frac{sin103}{66.26} =\frac{sin27.12}{31}=\frac{sinC}{52}$$

20. AbdullahM

But now that I look at the question again, they already gave you c as 52... and also, the angle became 60? o_0

21. anonymous

@AbdullahM This does not refer to to a previous post. This is a totally separate post

22. AbdullahM

oh, I get what you mean lol