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anonymous

  • one year ago

832 divisible by a. Divisible by 2 and 4 c. Divisible by 3, 5, 6, 9, and 10 b. Divisible by 6 and 10 d. Divisible by 2, 3, 4, 5, and 9

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  1. anonymous
    • one year ago
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    @princeharryyy

  2. anonymous
    • one year ago
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    Can someone show me how to find this out

  3. anonymous
    • one year ago
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    pleas!e help

  4. anonymous
    • one year ago
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    @DarkMoonZ could you help me out?

  5. anonymous
    • one year ago
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    @Nixy

  6. anonymous
    • one year ago
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    @mathmate

  7. princeharryyy
    • one year ago
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    2,4 is correct

  8. princeharryyy
    • one year ago
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    let me check the rest

  9. princeharryyy
    • one year ago
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    yeah! that's it...

  10. princeharryyy
    • one year ago
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    A is the answer. any number that has last digit 2,4,6,8,0 is divisible by 2. and any number whose last two digits are divisible by 4 is divisible by 4

  11. princeharryyy
    • one year ago
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    @HelpMePlease1999

  12. anonymous
    • one year ago
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    thanks, sorry I closed the tab thinking nobody wanted to help! Thank you!

  13. mathmate
    • one year ago
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    @princeharryyy Giving a direct answer without first explaining to asker how to solve the problem is against the code of conduct of OS. Please read: http://openstudy.com/code-of-conduct

  14. princeharryyy
    • one year ago
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    I guess I explained the answer @mathmate you are welcome @HelpMePlease1999 I was busy in some work. Didn't see the pop up color.

  15. mathmate
    • one year ago
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    Yes, you did explain, but afterwards. You need to explain first, and not give the answer (2,4) before the explanation, please. The reason is once the answer is given, the asker could have typed in the answer to the problem, and never come back to see the explanations, which is equivalent to giving a direct answer. Thank you for understanding and helping.

  16. princeharryyy
    • one year ago
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    thanks mate, sometimes we get busy in other work and don't have time to give the explanation... @mathmate but, i'll take care of it.

  17. mathmate
    • one year ago
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    Thank you! :)

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