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anonymous

  • one year ago

When a linear function has a slope of 5, what is the "run" part of the slope?

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  1. zzr0ck3r
    • one year ago
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    rise over run 5/1

  2. anonymous
    • one year ago
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    can't wait to see the answer to this!

  3. zzr0ck3r
    • one year ago
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    I assume this is what they meant....

  4. princeharryyy
    • one year ago
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    what's run @Lacey899

  5. AbdullahM
    • one year ago
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    There can be many answers. Without giving us the "rise" we can not solve for run. Rise could be 10, while run is 2, and at the end would still give us the same slope of 5...

  6. welshfella
    • one year ago
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    yep could be 10 million / 2 million

  7. anonymous
    • one year ago
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    it's a stupid name they came up with to represent the number on the denominator of the slope. Personally I prefer rise over lay

  8. AbdullahM
    • one year ago
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    o_0

  9. welshfella
    • one year ago
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    I don't like the terminology at all - I prefer the UK version which is 'vertical part / horizontal part of the slope' . However that's a lot of words...

  10. zzr0ck3r
    • one year ago
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    They are all misleading for this very reason...it is a ratio. In this question I would assume they meant for the fraction to be reduced, and it may even be defined that way in their book. I assume then that we are dealing with \(\dfrac{5}{1}\)

  11. zzr0ck3r
    • one year ago
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    If you guys wanted to be that particular you should be defining linear, because I bet it's not what you think :)

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