I've been having a touch of trouble with solving logarithms with uneven bases. For example 8^x-10=3^x+2
Now I know that in order to solve I need to
log8^x-10=log3^x+2
then you move the power out in front of the logs like so
x-10 log8=x+2 log3
this is where I stumble, you find the approximate value of the log soo
(x-10)(.903)=(x-2)(4.77)
It's after this step were I get lost.

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if it was (x-10)*2 = (x-2)*3
what would you do? I would distribute, and combine "like terms"

btw, I assume you meant log(3) = 0.47712 (not 4.77)

so do this
\[ (x-10)(.903)=(x-2)(0.477) \\
0.903x -9.03 = 0.477x -0.954
\]

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