Point X is located at (2, -6) and point Z is located at (0, 5). Find the y value for the point Y that is located the distance from point X to point Z. (4 points)
-3.6
-3.8
-4
-4.2

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- tw101

- katieb

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- anonymous

Wait, hm, is that the correct graph for this problem? The question mentions X Y and Z and I can't seem to find any of those on the shape.

- tw101

oh whoops! sorry wrong equation haha ignore that

- anonymous

It's ok! :P

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## More answers

- tw101

okay so you were saying

- tw101

okay so you were saying

- tw101

The bottom question is what i was asking

- anonymous

Is the original question the one you are confused on? the point X is located... etc?

- karatechopper

Is Y somewhere between X and Z? Almost forming a triangle shaped...?

- tw101

sorry about that one sec

- tw101

I figured out the weird triangle one, now I just have a question about the point x one

- karatechopper

Please rewrite the question below my comment, I am a bit confused about which exact question. Is the one that is your current question?

- tw101

- anonymous

@tw101 , are you familiar with the 'Distance Formula' at all?

- AbdullahM

I believe it wants the midpoint...

- anonymous

It says that point Y is located at the distance of point X to point Z, not between them I believe. But I could be mistaken.

- tw101

isnt it c^2=a^2+b^2?

- AbdullahM

"Find the y value for the point Y that is located the distance from point X to point Z."
It could be asking for what y-value is the same distance from x as from z.

- AbdullahM

Also, trying to find the distance of it would not get us anywhere and midpoint makes more sense.

- anonymous

Ah, okay that makes sense now

- AbdullahM

\(\sf\Large Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\)
and that is for two points: \(\sf (x_1,y_1)\) and \(\sf (x_2,y_2)\)

- tw101

okay give me a second to work it out:)

- AbdullahM

mhmm, the answer isn't there. So it isn't the midpoint :/

- tw101

wait im confused what do you mean

- tw101

i didnt get the right answer either...

- tw101

so what method can i use then..?

- AbdullahM

I'm not sure :/

- tw101

dang.. okay well thank you for your help anyways.

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