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anonymous

  • one year ago

The vertex of this parabola is at (-3,6). Which of the following could be it's equation? A. y=-3(x-3)^2-6 B. y=-3(x+3)^2-6 C. y=-3(x-3)^2+6 D. y=-3(x+3)^2+6

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  1. anonymous
    • one year ago
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    @Haseeb96 , @sourwing , @ybarrap

  2. anonymous
    • one year ago
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    Go read your algebra book. Seems like you still haven't fully grasp the concept

  3. Haseeb96
    • one year ago
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    what do you think which one is correct

  4. anonymous
    • one year ago
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    |dw:1434836286187:dw|

  5. ybarrap
    • one year ago
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    Which quadrant is this parabola in?

  6. anonymous
    • one year ago
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    2

  7. Haseeb96
    • one year ago
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    correct

  8. ybarrap
    • one year ago
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    This will tell you the signs for h and k what's the sign for h ? what's the sign for k?

  9. anonymous
    • one year ago
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    ++?

  10. Haseeb96
    • one year ago
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    no - and +

  11. ybarrap
    • one year ago
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    h is - but k is +

  12. Haseeb96
    • one year ago
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    @ybarrap he is correct

  13. ybarrap
    • one year ago
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    $$ y=a(x-h)+k $$ So what do we have now if we put in those signs?

  14. anonymous
    • one year ago
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    Which points are h and what are k again?

  15. ybarrap
    • one year ago
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    h is what moves this parabola left and right and k moves it up and down

  16. anonymous
    • one year ago
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    is it y=-3(-3)^2+6?

  17. Haseeb96
    • one year ago
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    no no

  18. Haseeb96
    • one year ago
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    y=-3(x-(-3))+6

  19. ybarrap
    • one year ago
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    Close h is associated with x and k is associated with y change $$ y=-3(-3)^2+6 $$ to $$ y=-3(\color{red}{x}-(-3))^2+6 $$

  20. anonymous
    • one year ago
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    so x+3

  21. anonymous
    • one year ago
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    Ohhhhh

  22. ybarrap
    • one year ago
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    that's right, negative times a negative gives you a positive

  23. Haseeb96
    • one year ago
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    because (h,k)=(-3,6) when we will put them in this equation y=-3(x-h)^2 + k we will get y=-3(x - (-3) )^2 + 6

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