The vertex of this parabola is at (-3,6). Which of the following could be it's equation? A. y=-3(x-3)^2-6 B. y=-3(x+3)^2-6 C. y=-3(x-3)^2+6 D. y=-3(x+3)^2+6

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The vertex of this parabola is at (-3,6). Which of the following could be it's equation? A. y=-3(x-3)^2-6 B. y=-3(x+3)^2-6 C. y=-3(x-3)^2+6 D. y=-3(x+3)^2+6

Geometry
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Go read your algebra book. Seems like you still haven't fully grasp the concept
what do you think which one is correct

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|dw:1434836286187:dw|
Which quadrant is this parabola in?
2
correct
This will tell you the signs for h and k what's the sign for h ? what's the sign for k?
++?
no - and +
h is - but k is +
@ybarrap he is correct
$$ y=a(x-h)+k $$ So what do we have now if we put in those signs?
Which points are h and what are k again?
h is what moves this parabola left and right and k moves it up and down
is it y=-3(-3)^2+6?
no no
y=-3(x-(-3))+6
Close h is associated with x and k is associated with y change $$ y=-3(-3)^2+6 $$ to $$ y=-3(\color{red}{x}-(-3))^2+6 $$
so x+3
Ohhhhh
that's right, negative times a negative gives you a positive
because (h,k)=(-3,6) when we will put them in this equation y=-3(x-h)^2 + k we will get y=-3(x - (-3) )^2 + 6

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