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anonymous

  • one year ago

How would I graph f(x)=27(1.3)x? (It's a exponential function so it has to be a curved line?)

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  1. anonymous
    • one year ago
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    I made a chart to help me understand but I'm not sure how.. x|f(x) ----- 0|27 1|- 2|- 3|- ---

  2. anonymous
    • one year ago
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    Would I just do like 27*1.3*2?

  3. Afrodiddle
    • one year ago
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    well let's fill in the chart

  4. anonymous
    • one year ago
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    would 1=35.1?

  5. Afrodiddle
    • one year ago
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    27(1.3) ^1

  6. anonymous
    • one year ago
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    oh

  7. anonymous
    • one year ago
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    so it would be 35.1

  8. Afrodiddle
    • one year ago
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    Yes

  9. anonymous
    • one year ago
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    First question...Is itf(x) = 27(1.3)^x or f(x)=27(1.3)x? f(x)=27(1.3)x f(1) = 27(1.3)(1) f(2) = 27(1.3)(2)

  10. anonymous
    • one year ago
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    then 2 would be 45.63?

  11. Afrodiddle
    • one year ago
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    It has to be 27(1.3) ^ x Other wise it's not exponential.

  12. anonymous
    • one year ago
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    ok

  13. anonymous
    • one year ago
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    Oh very true!

  14. anonymous
    • one year ago
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    would 2 be 45.63?

  15. Afrodiddle
    • one year ago
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    yes

  16. anonymous
    • one year ago
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    then 3 would be 59.319?

  17. anonymous
    • one year ago
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    so then i would plot like (0,27), (1,35.1) (2,45.63) and (3,59.319) with a curved line right?

  18. welshfella
    • one year ago
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    yes

  19. anonymous
    • one year ago
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    thank you :)

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