anonymous
  • anonymous
In operations the tanks will be filled with water and its specific weight is assumed to be 9.45 kN/m3. Write a program to show a graphical plot of the added weight (kN) of the tanks due to the liquid for the given range of spherical tank sizes (diameters in meters). What is it asking? I have already calculated the volumes of the tanks
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
I know I have to make a plot but the first sentence is throwing me off
anonymous
  • anonymous
So the problem gives you specific weight. This is more or less just density (which is mass/volume) times gravity to give a measurement of force/volume or in this case weight/volume. Best way to double check when you're given an unknown value is to look at the units. In this case its given as kN/m^3. kN is kilo Newtons or 1000 newtons where a Newton is a measure of force. m^3 is a distance cubed, or a measure of volume. Since you're given specific weight and you've already solved for volume, you'll just need to multiply the two together to get the added weight! and if you check the units, it works out: |dw:1434851562381:dw|
anonymous
  • anonymous
Thank you! @LifeEngineer

Looking for something else?

Not the answer you are looking for? Search for more explanations.