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anonymous
 one year ago
A 14cm chord and a 19cm chord intersect in a circle. The 14cm chord is divided into a 6cm segment and an 8cm segment. Find the lengths of the two segments into which the other chord is divided
anonymous
 one year ago
A 14cm chord and a 19cm chord intersect in a circle. The 14cm chord is divided into a 6cm segment and an 8cm segment. Find the lengths of the two segments into which the other chord is divided

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jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1434840159918:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1Let x = length of CE that means length of ED = 19  x dw:1434840292962:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1then you'll use the intersecting chords theorem http://www.mathopenref.com/chordsintersecting.html to say AE*EB = CE*ED 6*8 = x*(19x)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1solve 6*8 = x*(19x) for x to find the length of CE

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1does that make sense?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh yes, i didn't know that theorem
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