anonymous
  • anonymous
A 14-cm chord and a 19-cm chord intersect in a circle. The 14-cm chord is divided into a 6-cm segment and an 8-cm segment. Find the lengths of the two segments into which the other chord is divided
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Hello
anonymous
  • anonymous
I can help you
anonymous
  • anonymous
how do i do it?

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jim_thompson5910
  • jim_thompson5910
|dw:1434840159918:dw|
jim_thompson5910
  • jim_thompson5910
Let x = length of CE that means length of ED = 19 - x |dw:1434840292962:dw|
jim_thompson5910
  • jim_thompson5910
then you'll use the intersecting chords theorem http://www.mathopenref.com/chordsintersecting.html to say AE*EB = CE*ED 6*8 = x*(19-x)
jim_thompson5910
  • jim_thompson5910
solve 6*8 = x*(19-x) for x to find the length of CE
jim_thompson5910
  • jim_thompson5910
does that make sense?
anonymous
  • anonymous
oh yes, i didn't know that theorem

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