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In rectangle PQRS, PQ = 18, PS = 14, and PR = 22.8. Diagonals PR¯¯¯¯¯ and QS¯¯¯¯¯ intersect at point T. What is the length of TQ¯¯¯¯¯? A) 7 B) 9 C) 11.4 D) 22.8
|dw:1434843431272:dw| Diagonals of a rectangle intersect at their midpoint
Thank you MrNood. :)
find angle BAD by angle sum of a triangle then angle BCD = angle BAD opposite angles in a parallelogram are equal
so 34 or..?
in triangle BAD the 3 angle add up to 180 You know 2 of them - so you can work out
64?.. I think.
what is 83 + 34? then the 3rd angle make that add up to 180 (not 64)
does 83+34 + 113 = 180? if not then that is not the right answer 83+ 34 + ? = 180
I don't understand. This is like Algebra, no?
\[83+34 \neq 113\]
think of it as one of those solve for x problems 83+34 + x = 180
now you need to solve 83+34 first
So 117 - 180 should give me my answer, right?
x = 180-117 there solve that
yes it's 63
83 +34+ 63 all add up to 180
wow..you know it's been years since I've last done this...I forgot :O
Oh no. :( This one is definitely difficult for me. In fact, all of these are.
Geometry was so high school XD. That's almost 10 years ago buddy
Yeah, I'm in high school, sadly.
._. build a time machine back to 2006... xD
It was a simpler time for me then.
im looking at it now
Thank you. :)
hmm i honestly can not help you I am completely lost on it sorry! ill tag someone that might be able to help
Thank you. :) This is a difficult question, lol.
i have no idea sry i couldn`t help
Which set of vertices forms a parallelogram? A) A(2, 4), B(3, 3), C(6, 4), D(5, 6) B) A(-1, 1), B(2, 2), C(5, 1), D(4, 1) C) A(-5, -2), B(-3, 3), C(3, 5), D(1, 0) D) A(-1, 2), B(1, 3), C(5, 3), D(1, 1)
I think it's A, but I am not sure.
graph those on a piece of paper and then compare it to a real parallelogram
I failed, and I will try again tomorrow, but for now, I need sleep. Gute Nacht alles.