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anonymous

  • one year ago

Which of the following expressions is the inverse of the function y = x - 2 / 3? y = 3x + 2 y = 2x + 3 y = x - 3 / by 2 y = x + 2 / by 3

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  1. anonymous
    • one year ago
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    @jim_thompson5910

  2. jim_thompson5910
    • one year ago
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    Is the original \[\Large y = x - \frac{2}{3}\] or is the original \[\Large y = \frac{x-2}{3}\]

  3. anonymous
    • one year ago
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    The second one

  4. UsukiDoll
    • one year ago
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    lack of sleep .. T_T

  5. jim_thompson5910
    • one year ago
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    \[\Large y = \frac{x-2}{3}\] swap x and y \[\Large x = \frac{y-2}{3}\] now solve for y

  6. UsukiDoll
    • one year ago
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    hmmm I would get rid of the denominator by multiplying 3 all the way first and then swap x and y.

  7. jim_thompson5910
    • one year ago
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    either way works

  8. anonymous
    • one year ago
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    I'm not sure what to start with when solving for y.

  9. UsukiDoll
    • one year ago
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    \[\Large 3y = (3)\frac{x-2}{3} \rightarrow 3y=x-2\]

  10. UsukiDoll
    • one year ago
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    then swap x and y . In other words switch places ...

  11. UsukiDoll
    • one year ago
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    \[\large 3x=y-2\]

  12. UsukiDoll
    • one year ago
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    and then solve for y...this would be much easier because I got rid of the fraction first by multiplying the entire equation by 3

  13. UsukiDoll
    • one year ago
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    so what do we need to do to have y by itself

  14. anonymous
    • one year ago
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    3x=y-2 +2 +2 5x=y

  15. jim_thompson5910
    • one year ago
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    3x and 2 are NOT like terms

  16. UsukiDoll
    • one year ago
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    ummmm 3x+2 is not combinable

  17. jim_thompson5910
    • one year ago
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    you cannot say 3x+2 turns into 5x or 5

  18. anonymous
    • one year ago
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    Oh. Sorry.

  19. UsukiDoll
    • one year ago
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    because 3x has a number and variable 2 is just a number... it can't be combined

  20. anonymous
    • one year ago
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    Ok... how do I isolate y.

  21. UsukiDoll
    • one year ago
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    y has to be by itself... \[\large 3x=y-2 \] so what do we need to do to have y by itself... y is destined to be alone xD

  22. jim_thompson5910
    • one year ago
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    unheard, when you added 2 to both sides, you were on the right path

  23. jim_thompson5910
    • one year ago
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    3x = y - 2 +2 +2 3x + 2 = y y = 3x + 2

  24. UsukiDoll
    • one year ago
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    :( ! why jim why

  25. jim_thompson5910
    • one year ago
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    you just leave 3x+2 as it is since you cannot combine those terms

  26. anonymous
    • one year ago
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    Oh, thank you Jim.

  27. jim_thompson5910
    • one year ago
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    she already had it usukidoll

  28. anonymous
    • one year ago
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    Thank you both.

  29. UsukiDoll
    • one year ago
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    jim's version would have required fractions to be split up \[\Large x = \frac{y-2}{3} \rightarrow x = \frac{y}{3}-\frac{2}{3}\] \[\Large x + \frac{2}{3} = \frac{y}{3}\] and then multiply 3 throughout the equation... too long...but another way to check \[ \Large 3x+2=y\]

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