anonymous
  • anonymous
Using the completing-the-square method, find the vertex of the function f(x) = –2x2 + 12x + 5 and indicate whether it is a minimum or a maximum and at what point.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
it is a maximum because the leading coefficient|dw:1434844163162:dw| is negative so the parabola opens down
campbell_st
  • campbell_st
|dw:1434843957618:dw|
anonymous
  • anonymous
Ok:)

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
\[ f(x) = –2x^2 + 12x + 5 \]to find the vertex, the first coordinate of the vertex is always \[-\frac{b}{2a}\] which in your case is \[-\frac{12}{2\times (-2)}\]
anonymous
  • anonymous
the second coordinate of the vertex is what you get when you replace \(x\) by the first coordinate
anonymous
  • anonymous
3
dmndlife24
  • dmndlife24
Graph opens downward so it would be a maximum point Vertex formula|dw:1434844392512:dw|
anonymous
  • anonymous
yeah that is the first coordinate the second coordinate if \(f(3)\)
anonymous
  • anonymous
Now what do I do?
anonymous
  • anonymous
have a beer you are done
campbell_st
  • campbell_st
well completing the square \[f(x) = (-2x^2 + 12x) + 5\] factor out -2 \[f(x) = -2(x^2 - 6x) + 5\] now complete the square in x
anonymous
  • anonymous
So is it maximum or minimum??
anonymous
  • anonymous
, find the vertex of the function \[(3,23)\] it is a max have a nice day
anonymous
  • anonymous
Solve x2 + 12x + 6 = 0 using the completing-the-square method.
anonymous
  • anonymous
Thanks friend. I also need help with that one
anonymous
  • anonymous
|dw:1434844578090:dw|
campbell_st
  • campbell_st
so inside the brackets you need to add (-6/2)^2 so the function is \[f(x) = -2(x^2 - 6x + 9) + 5 -18\] which becomes f(x) = -2(x -3)^2 - 13 now you have completed the square have the equation in vertex form and can answer the question using the required method
campbell_st
  • campbell_st
|dw:1434844393236:dw|
anonymous
  • anonymous
\[x^2 + 12x + 6 = 0 \\ x^2+12x=-6\] is a start
anonymous
  • anonymous
hahahah you're funny @satellite73 !!!
anonymous
  • anonymous
I see, I see
anonymous
  • anonymous
|dw:1434844713212:dw|
anonymous
  • anonymous
Ok answer the other question please because I'm confused
campbell_st
  • campbell_st
|dw:1434844498447:dw|
anonymous
  • anonymous
\[x^2+12x=-6\]takes two steps to complete the square what is half of 12?
anonymous
  • anonymous
6
anonymous
  • anonymous
right, and what is \(6^2\_?
anonymous
  • anonymous
oops what is \(6^2\)?
anonymous
  • anonymous
36
anonymous
  • anonymous
so go right from \[x^2+12x=-6\] to \[(x+6)^2=-6+36\] or \[(x+6)^2=30\]
anonymous
  • anonymous
then take the square root of both sides, don't forget the \(\pm\) and get \[x+6=\pm\sqrt{30}\]
anonymous
  • anonymous
subtract 6 and you are done
anonymous
  • anonymous
so is it 6 plus or negative radical 30?
anonymous
  • anonymous
no
anonymous
  • anonymous
SUBTRACT 6 to solve for \(x\)
anonymous
  • anonymous
|dw:1434844993983:dw|
anonymous
  • anonymous
nope
anonymous
  • anonymous
|dw:1434845032667:dw|
anonymous
  • anonymous
|dw:1434845026665:dw|
anonymous
  • anonymous
yeah that one

Looking for something else?

Not the answer you are looking for? Search for more explanations.