## anonymous one year ago Solve for x. −ax + 3b > 5 x > the quantity 3 times b minus 5 all over a x > the quantity 5 minus 3 times b all over negative a x < the quantity 3 times b plus 5 all over a x < the quantity negative 3 times b plus 5 all over negative a

1. First subtract 3b over to other side. 2. Divide by -a to change inequality sign to opposite since -a is negative. 3. Answer: $-ax+3b>5\rightarrow -ax>5-3b \rightarrow x<(5-3b)/(-a)$