Find the standard form of the equation of the parabola with a focus at (0, -10) and a directrix at y = 10. (5 points) y = -1/10x2 y =-1/40 x2 y2 = -40x y2 = -10x

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Find the standard form of the equation of the parabola with a focus at (0, -10) and a directrix at y = 10. (5 points) y = -1/10x2 y =-1/40 x2 y2 = -40x y2 = -10x

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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did you make a sketch?
no... @sourwing
perhaps you should make a sketch now?

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how??
there is a blue [draw] button below. Click that and draw
i don't know how to draw.
the general equation for a parabole whose focus is: F=(0, p/2) and whose directrix is: y= -p/2, is: \[\Large {x^2} = 2py\] now, using your data we have: \[\Large \frac{p}{2} = - 10\] so, what is p=...? then substitute that value of p, into my equation above, so you will get your answer
parabola*

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