Here's a fun question I found that has a simple fun answer, try it out.
\(\bar x\) is an eigenvector with corresponding eigenvalue\(\lambda\) of the matrix product AB where A and B are both invertible matrices:
$$AB \bar x = \lambda \bar x$$
Show that \(\lambda\) is an eigenvalue of the matrix BA

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both invertible matrices.. like non-singular...as in there's an inverse.

Essentially, we have to show that BAx = lambda x

O_O the Latex just exploded.

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