## anonymous one year ago A 0.200 kg block of a substance requires 3.59 kJ of heat to raise its temperature by 20.0 K. What is the specific heat of the substance? A. 2,020 J/(kg * K) B. 383 J/(kg*K) C. 130 J/(kg * K) D. 897 J/(kg*K)

1. Michele_Laino

the requested specific heat c is: $\large c = \frac{1}{m}\frac{Q}{{\Delta t}} = \frac{1}{{0.2}}\frac{{3.59}}{{20}} = ...\left( {Kjoules/Kg \times K} \right)$

2. anonymous

we get 0.8975? and converting we get choice D as our answer?

3. Michele_Laino

that's right!

4. anonymous

yay! thansk!!

5. Michele_Laino

:)