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anonymous

  • one year ago

Can someone prove to me how exactly is the other angle for this is 150???

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    I solved it up till 30 degrees but then they're saying the "since AC is the largest side" I don't get it

  3. butterflydreamer
    • one year ago
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    do you remember your unit circle?

  4. anonymous
    • one year ago
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    yea

  5. butterflydreamer
    • one year ago
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    So do you remember that when we have sine of an angle, it can have two values?

  6. anonymous
    • one year ago
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    yea you minus 30 180 yea I know that but visually I just can't imagine it in this triangle

  7. anonymous
    • one year ago
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    30 minus from 180

  8. butterflydreamer
    • one year ago
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    yeah, that's how you get 150 degrees... If theta = 30, it means that angle ABC and angle ACB would be larger than 30 true? Since the ANGLE SUM of a triangle = 180 right? If |dw:1434891872359:dw|

  9. anonymous
    • one year ago
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    wait so what I'm understanding from this that sum of angle ABC and ACB is 150??

  10. butterflydreamer
    • one year ago
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    not quite... Just remember that the angle that corresponds to the longest side of a triangle has the largest angle

  11. anonymous
    • one year ago
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    Ok I still don't 100% get it. Okay like suppose I don't that there was possibly another length of AC that is longer. compare to when it is if you have our theta as 30 degrees. How do you prove that the other angle of theta would be 150 by calculation??

  12. anonymous
    • one year ago
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    *don't know

  13. butterflydreamer
    • one year ago
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    |dw:1434892380598:dw| So when dealing with sine there are two values... but to test it, you consider the ambigous case. So if you have the other angles, you can add them all up and make sure that they equal to 180 (since the angle sum of a triangle = 180)

  14. anonymous
    • one year ago
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    |dw:1434892581440:dw|

  15. anonymous
    • one year ago
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    is this what you're saying..?

  16. anonymous
    • one year ago
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    This is what's given in my text book ofc I didn't understand it first but after some while I pictured it to be in that way as you drew in the unit circle diagram. The thing is trying to put our triangle into this unit cirle I can't imagine how I'd do that..

  17. anonymous
    • one year ago
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    lets see |dw:1434892824826:dw|

  18. anonymous
    • one year ago
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    uhh.. you mean like this right? |dw:1434892995285:dw|

  19. anonymous
    • one year ago
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    oh no nvm, they showed you the formula using area.

  20. anonymous
    • one year ago
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    I, though, haven't seen the formula using area.

  21. anonymous
    • one year ago
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    apologize

  22. anonymous
    • one year ago
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    I know the answer sir And the know the methods used to find 30 what I'm looking for is the proof for 150 degrees

  23. hartnn
    • one year ago
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    30 can not be the largest angle of any triangle. The sum of 3 angles must be 180.

  24. hartnn
    • one year ago
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    if 30 is the largest, the other 2 angles are less than 30 and their sum is max 90...

  25. anonymous
    • one year ago
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    @hartnn Wait wait lets not go there. can we just stick to the unit circle? it's much easier for me to understand. Look cause I'm trying to put the triangle from our original question into the unit circle. |dw:1434894775692:dw| I just wanna know if I'm visually imagining it correctly. Thats all

  26. hartnn
    • one year ago
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    yes thats correct. so now label side AC

  27. anonymous
    • one year ago
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    |dw:1434895631747:dw| @hartnn Thanks a BUNCH!

  28. hartnn
    • one year ago
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    correct :) welcome ^_^

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