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Find the area enclosed by the region in sq units described by \(\large \color{black}{\begin{align} & 0=x=5\ \text{and} \ 0\leq |y| \leq 8\hspace{.33em}\\~\\~\\~\\~\\ & a.)\ 40 \hspace{.33em}\\~\\ & b.) \ 80 \hspace{.33em}\\~\\ & c.)\ 160 \hspace{.33em}\\~\\ & d.)\ 120 \hspace{.33em}\\~\\ \end{align}}\)
|dw:1434892308089:dw|
what do u mean by 0=x=5 ?? how is that even possible ?

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i havent framed the question , it is from the book
hmm interesting , so 0=x=5 has no solution on what i see, unless u have other hypotheses
maybe 0<=x<=5.....
idk where would x goes to :( |dw:1434892583073:dw|
or 0=x=5 means two conditions. 1)x=0 2)x=5 saying that these 2 conditions are the boundaries
so yeah, I guess it would be just a square 5 by 8 units, like ikram drew.
that's weird? a number can't equal two fixed values at once?
yes 0=x=5 is false cause that implies 0=5, there is another way to set x to two fixed points which is x=0 and x=5 :D
yeah that would be the same as 0<=x<=5
well no not the same
i am getting answer as \(80\) from \(x=0\) and \(x=5\) \(|y|\leq 8\)
oh yeah that's correct
area 80 is correct ?
oh no i was replying to ikram
|dw:1434893225913:dw| |dw:1434893259512:dw|
the second graph for x=0 and x=5 it would give two points with coordinates of (0,somewhere btw 0 and 8) and (5,somewhere btw 0 and 8)
oh wait my bad sorry :( u said enclosed by the region
then no problem 80 is correct
yesterday i was told that |y|≤a where a is constant other than 0 has 2 inqualities
i don't see how it is 80?
40 -.-
too hungry man @xapproachesinfinity
yeah i know you are :)
lol i m confused about the answer is it 80 or 40
well it thought it was 40 as for 80 i have no idea did you get that!
|dw:1434894148013:dw|
is that corrrect
but you |y|>0 already
have*
ohk i see
so is this \(0\leq |y| \leq 8\) equal to \(0\leq y \leq 8\)
well let's decompose that |y|>0 mean that for any y |y|>0 so y>0 or y<0 and |y|<8 implies -80 so we throw off that -8
by the above interpretation u mean \(0\leq |y| \leq 8\) \(\implies 0\leq y\leq 8\) ?
yeah seems that
looks little strange
yeah why?
@xapproachesinfinity I am not with you!! (-8,8 ) is my choice
How can \(0\leq |y|\leq 8\) turn to \(0\leq y\leq 8\)??
the book answer is given as \(\Large 80\) btw
see my explanation above
lol
hmm i don't see have it is 80?
how *
I saw it, but still think it is invalid
\(0\leq |y|\) is the distracting part. It is ALWAYS.
|dw:1434895407325:dw|
yup.
|y|>0 implies y>0 or y<0 mean for any values of y
hmm
i'm still not convinced that y is in [-8,8]
if i put a value \(-5\) then it satisfies the criteria for \(0\leq |y|\leq 8\)
and so is \(-8\)
ok fair enough :)
so u r convinced i think
yes!

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