## mathmath333 one year ago question

1. mathmath333

Find the area enclosed by the region in sq units described by \large \color{black}{\begin{align} & 0=x=5\ \text{and} \ 0\leq |y| \leq 8\hspace{.33em}\\~\\~\\~\\~\\ & a.)\ 40 \hspace{.33em}\\~\\ & b.) \ 80 \hspace{.33em}\\~\\ & c.)\ 160 \hspace{.33em}\\~\\ & d.)\ 120 \hspace{.33em}\\~\\ \end{align}}

2. ikram002p

|dw:1434892308089:dw|

3. ikram002p

what do u mean by 0=x=5 ?? how is that even possible ?

4. mathmath333

i havent framed the question , it is from the book

5. ikram002p

hmm interesting , so 0=x=5 has no solution on what i see, unless u have other hypotheses

6. anonymous

maybe 0<=x<=5.....

7. ikram002p

idk where would x goes to :( |dw:1434892583073:dw|

8. anonymous

or 0=x=5 means two conditions. 1)x=0 2)x=5 saying that these 2 conditions are the boundaries

9. anonymous

so yeah, I guess it would be just a square 5 by 8 units, like ikram drew.

10. xapproachesinfinity

that's weird? a number can't equal two fixed values at once?

11. ikram002p

yes 0=x=5 is false cause that implies 0=5, there is another way to set x to two fixed points which is x=0 and x=5 :D

12. xapproachesinfinity

yeah that would be the same as 0<=x<=5

13. ikram002p

well no not the same

14. mathmath333

i am getting answer as $$80$$ from $$x=0$$ and $$x=5$$ $$|y|\leq 8$$

15. xapproachesinfinity

oh yeah that's correct

16. mathmath333

area 80 is correct ?

17. xapproachesinfinity

oh no i was replying to ikram

18. ikram002p

|dw:1434893225913:dw| |dw:1434893259512:dw|

19. ikram002p

the second graph for x=0 and x=5 it would give two points with coordinates of (0,somewhere btw 0 and 8) and (5,somewhere btw 0 and 8)

20. ikram002p

oh wait my bad sorry :( u said enclosed by the region

21. ikram002p

then no problem 80 is correct

22. mathmath333

yesterday i was told that |y|≤a where a is constant other than 0 has 2 inqualities

23. xapproachesinfinity

i don't see how it is 80?

24. ikram002p

40 -.-

25. ikram002p

too hungry man @xapproachesinfinity

26. xapproachesinfinity

|y|<a mean -a<y<a @math

27. xapproachesinfinity

yeah i know you are :)

28. mathmath333

lol i m confused about the answer is it 80 or 40

29. xapproachesinfinity

well it thought it was 40 as for 80 i have no idea did you get that!

30. mathmath333

|dw:1434894148013:dw|

31. mathmath333

is that corrrect

32. xapproachesinfinity

33. xapproachesinfinity

have*

34. mathmath333

ohk i see

35. mathmath333

so is this $$0\leq |y| \leq 8$$ equal to $$0\leq y \leq 8$$

36. xapproachesinfinity

well let's decompose that |y|>0 mean that for any y |y|>0 so y>0 or y<0 and |y|<8 implies -8<y<8 but then we just said y>0 so we throw off that -8

37. mathmath333

by the above interpretation u mean $$0\leq |y| \leq 8$$ $$\implies 0\leq y\leq 8$$ ?

38. xapproachesinfinity

yeah seems that

39. mathmath333

looks little strange

40. xapproachesinfinity

yeah why?

41. Loser66

@xapproachesinfinity I am not with you!! (-8,8 ) is my choice

42. Loser66

How can $$0\leq |y|\leq 8$$ turn to $$0\leq y\leq 8$$??

43. mathmath333

the book answer is given as $$\Large 80$$ btw

44. xapproachesinfinity

see my explanation above

45. mathmath333

lol

46. xapproachesinfinity

hmm i don't see have it is 80?

47. xapproachesinfinity

how *

48. Loser66

I saw it, but still think it is invalid

49. Loser66

$$0\leq |y|$$ is the distracting part. It is ALWAYS.

50. mathmath333

|dw:1434895407325:dw|

51. Loser66

yup.

52. xapproachesinfinity

|y|>0 implies y>0 or y<0 mean for any values of y

53. xapproachesinfinity

hmm

54. xapproachesinfinity

i'm still not convinced that y is in [-8,8]

55. mathmath333

if i put a value $$-5$$ then it satisfies the criteria for $$0\leq |y|\leq 8$$

56. mathmath333

and so is $$-8$$

57. xapproachesinfinity

ok fair enough :)

58. mathmath333

so u r convinced i think

59. xapproachesinfinity

yes!