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mathmath333

  • one year ago

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  1. mathmath333
    • one year ago
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    Find the area enclosed by the region in sq units described by \(\large \color{black}{\begin{align} & 0=x=5\ \text{and} \ 0\leq |y| \leq 8\hspace{.33em}\\~\\~\\~\\~\\ & a.)\ 40 \hspace{.33em}\\~\\ & b.) \ 80 \hspace{.33em}\\~\\ & c.)\ 160 \hspace{.33em}\\~\\ & d.)\ 120 \hspace{.33em}\\~\\ \end{align}}\)

  2. ikram002p
    • one year ago
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    |dw:1434892308089:dw|

  3. ikram002p
    • one year ago
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    what do u mean by 0=x=5 ?? how is that even possible ?

  4. mathmath333
    • one year ago
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    i havent framed the question , it is from the book

  5. ikram002p
    • one year ago
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    hmm interesting , so 0=x=5 has no solution on what i see, unless u have other hypotheses

  6. anonymous
    • one year ago
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    maybe 0<=x<=5.....

  7. ikram002p
    • one year ago
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    idk where would x goes to :( |dw:1434892583073:dw|

  8. anonymous
    • one year ago
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    or 0=x=5 means two conditions. 1)x=0 2)x=5 saying that these 2 conditions are the boundaries

  9. anonymous
    • one year ago
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    so yeah, I guess it would be just a square 5 by 8 units, like ikram drew.

  10. xapproachesinfinity
    • one year ago
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    that's weird? a number can't equal two fixed values at once?

  11. ikram002p
    • one year ago
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    yes 0=x=5 is false cause that implies 0=5, there is another way to set x to two fixed points which is x=0 and x=5 :D

  12. xapproachesinfinity
    • one year ago
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    yeah that would be the same as 0<=x<=5

  13. ikram002p
    • one year ago
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    well no not the same

  14. mathmath333
    • one year ago
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    i am getting answer as \(80\) from \(x=0\) and \(x=5\) \(|y|\leq 8\)

  15. xapproachesinfinity
    • one year ago
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    oh yeah that's correct

  16. mathmath333
    • one year ago
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    area 80 is correct ?

  17. xapproachesinfinity
    • one year ago
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    oh no i was replying to ikram

  18. ikram002p
    • one year ago
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    |dw:1434893225913:dw| |dw:1434893259512:dw|

  19. ikram002p
    • one year ago
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    the second graph for x=0 and x=5 it would give two points with coordinates of (0,somewhere btw 0 and 8) and (5,somewhere btw 0 and 8)

  20. ikram002p
    • one year ago
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    oh wait my bad sorry :( u said enclosed by the region

  21. ikram002p
    • one year ago
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    then no problem 80 is correct

  22. mathmath333
    • one year ago
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    yesterday i was told that |y|≤a where a is constant other than 0 has 2 inqualities

  23. xapproachesinfinity
    • one year ago
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    i don't see how it is 80?

  24. ikram002p
    • one year ago
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    40 -.-

  25. ikram002p
    • one year ago
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    too hungry man @xapproachesinfinity

  26. xapproachesinfinity
    • one year ago
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    |y|<a mean -a<y<a @math

  27. xapproachesinfinity
    • one year ago
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    yeah i know you are :)

  28. mathmath333
    • one year ago
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    lol i m confused about the answer is it 80 or 40

  29. xapproachesinfinity
    • one year ago
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    well it thought it was 40 as for 80 i have no idea did you get that!

  30. mathmath333
    • one year ago
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    |dw:1434894148013:dw|

  31. mathmath333
    • one year ago
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    is that corrrect

  32. xapproachesinfinity
    • one year ago
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    but you |y|>0 already

  33. xapproachesinfinity
    • one year ago
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    have*

  34. mathmath333
    • one year ago
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    ohk i see

  35. mathmath333
    • one year ago
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    so is this \(0\leq |y| \leq 8\) equal to \(0\leq y \leq 8\)

  36. xapproachesinfinity
    • one year ago
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    well let's decompose that |y|>0 mean that for any y |y|>0 so y>0 or y<0 and |y|<8 implies -8<y<8 but then we just said y>0 so we throw off that -8

  37. mathmath333
    • one year ago
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    by the above interpretation u mean \(0\leq |y| \leq 8\) \(\implies 0\leq y\leq 8\) ?

  38. xapproachesinfinity
    • one year ago
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    yeah seems that

  39. mathmath333
    • one year ago
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    looks little strange

  40. xapproachesinfinity
    • one year ago
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    yeah why?

  41. Loser66
    • one year ago
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    @xapproachesinfinity I am not with you!! (-8,8 ) is my choice

  42. Loser66
    • one year ago
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    How can \(0\leq |y|\leq 8\) turn to \(0\leq y\leq 8\)??

  43. mathmath333
    • one year ago
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    the book answer is given as \(\Large 80\) btw

  44. xapproachesinfinity
    • one year ago
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    see my explanation above

  45. mathmath333
    • one year ago
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    lol

  46. xapproachesinfinity
    • one year ago
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    hmm i don't see have it is 80?

  47. xapproachesinfinity
    • one year ago
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    how *

  48. Loser66
    • one year ago
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    I saw it, but still think it is invalid

  49. Loser66
    • one year ago
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    \(0\leq |y|\) is the distracting part. It is ALWAYS.

  50. mathmath333
    • one year ago
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    |dw:1434895407325:dw|

  51. Loser66
    • one year ago
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    yup.

  52. xapproachesinfinity
    • one year ago
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    |y|>0 implies y>0 or y<0 mean for any values of y

  53. xapproachesinfinity
    • one year ago
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    hmm

  54. xapproachesinfinity
    • one year ago
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    i'm still not convinced that y is in [-8,8]

  55. mathmath333
    • one year ago
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    if i put a value \(-5\) then it satisfies the criteria for \(0\leq |y|\leq 8\)

  56. mathmath333
    • one year ago
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    and so is \(-8\)

  57. xapproachesinfinity
    • one year ago
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    ok fair enough :)

  58. mathmath333
    • one year ago
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    so u r convinced i think

  59. xapproachesinfinity
    • one year ago
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    yes!

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