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- mathmath333

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- mathmath333

Find the area enclosed by the region in sq units described by
\(\large \color{black}{\begin{align} & 0=x=5\ \text{and} \ 0\leq |y| \leq 8\hspace{.33em}\\~\\~\\~\\~\\
& a.)\ 40 \hspace{.33em}\\~\\
& b.) \ 80 \hspace{.33em}\\~\\
& c.)\ 160 \hspace{.33em}\\~\\
& d.)\ 120 \hspace{.33em}\\~\\
\end{align}}\)

- ikram002p

|dw:1434892308089:dw|

- ikram002p

what do u mean by 0=x=5 ?? how is that even possible ?

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## More answers

- mathmath333

i havent framed the question , it is from the book

- ikram002p

hmm interesting , so 0=x=5 has no solution on what i see, unless u have other hypotheses

- anonymous

maybe 0<=x<=5.....

- ikram002p

idk where would x goes to :(
|dw:1434892583073:dw|

- anonymous

or 0=x=5 means two conditions.
1)x=0
2)x=5
saying that these 2 conditions are the boundaries

- anonymous

so yeah, I guess it would be just a square 5 by 8 units, like ikram drew.

- xapproachesinfinity

that's weird? a number can't equal two fixed values at once?

- ikram002p

yes 0=x=5 is false cause that implies 0=5, there is another way to set x to two fixed points which is x=0 and x=5 :D

- xapproachesinfinity

yeah that would be the same as 0<=x<=5

- ikram002p

well no not the same

- mathmath333

i am getting answer as \(80\) from \(x=0\) and \(x=5\) \(|y|\leq 8\)

- xapproachesinfinity

oh yeah that's correct

- mathmath333

area 80 is correct ?

- xapproachesinfinity

oh no i was replying to ikram

- ikram002p

|dw:1434893225913:dw|
|dw:1434893259512:dw|

- ikram002p

the second graph for x=0 and x=5 it would give two points with coordinates of
(0,somewhere btw 0 and 8) and (5,somewhere btw 0 and 8)

- ikram002p

oh wait my bad sorry :( u said enclosed by the region

- ikram002p

then no problem 80 is correct

- mathmath333

yesterday i was told that |y|â‰¤a where a is constant other than 0 has 2 inqualities

- xapproachesinfinity

i don't see how it is 80?

- ikram002p

40 -.-

- ikram002p

too hungry man @xapproachesinfinity

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