- rvc

If
aN implies S
eF implies I
gH implies M
then nS implies ?

- jamiebookeater

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- rvc

The options are :
1)T
2)A
3)L
4)K

- rvc

- rvc

what is the logic?

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## More answers

- Loser66

I am trying but not find out yet. ha!!

- Loser66

I don't know!! I am sorry.

- rvc

okay
thanks for trying @Loser66

- princeharryyy

eF implies I or L @rvc

- rvc

I

- princeharryyy

ok! let me ntry n find the connection.

- anonymous

I think its K... I have a weird reason... is the answer known to you @rvc?

- rvc

no
i dont know the ans

- mathmath333

What is the source of the question is it related to mathamatics .

- rvc

yeah

- Loser66

@mathmath333 it's called encryption maths

- mathmath333

ok i see @Loser66

- freckles

hey @rvc can I asked where this question came from?

- rvc

This question is from NET Exam

- freckles

Can I find that exam on the internet?

- rvc

i dont know
you may please try :)

- freckles

so loser said it had something to do with encryption
is there anything else you can tell me about this problem?
Like there are all kinds of encryption systems...
I guess this is a mathematics Net exam?

- rvc

ah
The question doesnt give any more information

- Empty

Since aN implies S then backwards we have while changing the case to match: nS implies A.
A is an answer choice, but this is a super weak reason for this to be the answer haha.

- freckles

if nothing else was given how did loser know this had something to do with encryption?

- dan815

|dw:1434952460774:dw|

- freckles

all I did 1-26 for capital letters
and 27-52 for lower case letters
didn't find a pattern

- rvc

:/

- dan815

you..

- dan815

why are u still here, family reunion boy

- Empty

I was considering the rotational and reflectional symmetries of the letters and also considering their placement on a keyboard to see if there was a relationship, also vowels and consonants, still nothing.
I don't leave until tomorrow dan lol

- Empty

The only patterns I'm seeing are:
lower case, upper case implies upper case
and the answer choices spell out TALK.

- Empty

Honestly if someone can legit figure this out in a way that's reasonable, I'll give you a medal + fan. lol

- rvc

|dw:1434952862606:dw|

- dan815

|dw:1434952911473:dw|

- Empty

|dw:1434952901247:dw|

- dan815

|dw:1434952934158:dw|

- rvc

by so on i meant the full question because its hard to draw here @Empty

- Empty

@dan815 do you mean this? http://prntscr.com/7jtxyu

- dan815

the 5,6 =>9
and 7,8=>13 makes me think maybe there is apttern with numbers
its like +2 for each number ?

- Empty

Ok what's the sequence:
1,1,2,...?

- freckles

do i get to answer that? :p
or should rvc get to answer that @empty ?

- dan815

i am not answering these questions, its never what it it looks like with u

- dan815

lol

- Empty

No this is open for anyone, answer away @freckles it's all yours :)

- freckles

it looks like the first few terms of the fibnocci sequence you have written

- Empty

Sorry that's not it try again

- dan815

lol

- dan815

1,1,2,2

- Empty

Sorry the next term in the sequence is http://prntscr.com/7jtyvr. I'll give you a medal if you can write the function for the nth term, it's a simple expression

- dan815

1,1,2,3,4,5

- rvc

im confused

- Empty

Whoops I had put a period at the end. http://prntscr.com/7jtyvr

- Empty

@rvc This problem is impossible and I'm giving an example of a problem that looks just as simple that's equally as nonsensical and ambiguous.

- freckles

@rvc would it be against any copyright rules or laws or whatever if you posted a picture of that question? Or like even better and if not too much trouble can you copy and send the whole exam thing ?
I still don't get it. Maybe I can get a better feel for the problem based on the other questions.

- Empty

By the way the formula for the nth term of my series is starting from 0, 1,2,3, etc...
f(n)=n!!!!!

- freckles

https://www.google.com/url?sa=t&rct=j&q=&esrc=s&source=web&cd=1&cad=rja&uact=8&ved=0CB4QFjAA&url=http%3A%2F%2Fwww.csirhrdg.res.in%2Fms_mp.pdf&ei=S6eHVZ36CMe1yATYo6TIDw&usg=AFQjCNEC6aeMz6GHPRUzIqLmgcEKJYvLpg
I found this but this doesn't have any similar questions.

- Empty

The answer seems to be T because it's the only way to maintain the pattern that the letters are always in alphabetical order.

- rvc

oh okay
please wait

- freckles

That is a interesting answer @Empty
and is probably more possible then the other
but I don't know :p

- Empty

Yeah see this is garbage

- rvc

##### 1 Attachment

- rvc

The 14th question

- freckles

well cookie! I'm still lost. I will have to think more about this question tomorrow because it is 1:27 AM.
Sorry @rvc . :(

- rvc

thank you so much for your effort @freckles

- dan815

so are we agreeing on T

- Empty

The T argument is just as good as the A argument. I'm not convinced the alphabetical order isn't just some coincidence because there's no sort of equal spacing between the letters at all.

- rvc

so T is the ans?

- Empty

That's not what I'm saying at all

- Empty

I'm saying this is a terrible problem and I feel bad that this is a test question.

- ganeshie8

lol #14 and #15 look more like reasoning problems which everybody hates because they are a bit ambiguous and not so regular mathy

- rvc

15th is easy

- ganeshie8

im actually trying both #14 and #15 in parallel w/o any success
whats the solution for #15 ?

- rvc

15th : |dw:1434956874159:dw|

- ganeshie8

that's so cool !

- rvc

yep
but the 14th and 16th is not cool lol
what about 12th?

- ganeshie8

#12 should be
number of black marbles in W = number of white marbles in B
because whatever the new white marbles in B, they have come from the jar W

- rvc

|dw:1434957539577:dw|

- rvc

|dw:1434957746502:dw|

- ganeshie8

In 3rd case, notice that you have "40 white" and "10 black" marbles in jarW.
Suppose you randomly pick "x white" and "10-x black" marbles from jarW and put them in jarB. Then the number of black marbles left behind in jarW would be ?

- jim_thompson5910

#14
This is my guess. I could be way off.
aN => S
eF => I
gH => M
flip the letters in the first part to get
Na => S
Fe => I
Hg => M
we have Na, Fe, Hg. All code names for elements on the periodic table
Na = Sodium which starts with an S. So that explains Na => S
Fe = Iron, so that explains Fe => I
Hg = Mercury, explains Hg => M
So nS turns into Sn which is Tin
So I'm thinking that Sn => T which means nS => T
It's the only thing that comes to mind which makes sense because it fits, but at the same time, this is chemistry material (which doesn't fit in a math test).

- rvc

hmmm idk @ganeshie8 black marble will be 10-x =y

- rvc

wow
congrats!!!!
@jim_thompson5910 Thank youuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

- ganeshie8

wow @jim_thompson5910 that should be it xD

- jim_thompson5910

it might be that or something way different

- rvc

you proved it

- rvc

what about the rest :/

- ganeshie8

For #16, you may use 30-60-90 triangle
|dw:1434959042367:dw|

- rvc

what should i do next @ganeshie8 ?

- ganeshie8

use 30-60-90 triangle or directly go for trig to find the lengths of other sides in that right triangle in terms of R

- rvc

|dw:1434959598398:dw|

- rvc

@ganeshie8 please help

- jim_thompson5910

@rvc, do you see how point C is R units away from A? The question is pretty much answered at this point

- rvc

yep i found that :)
thank you so much @jim_thompson5910

- rvc

@jim_thompson5910
what about the 12th one?

- rvc

- anonymous

So exercise 12 is about probability...

- rvc

yep

- anonymous

hi, I can't understand the question

- rvc

:/

- rvc

which one ?
the 12th one?
did you see that file?

- anonymous

Alright!
Let the number of white balls in Box W be 40 whites and that in box B, 40 black balls.
After ten black balls being transferred to box W, the probability of encountering a white ball at any pick is \[P _{w}=\frac{ 40 }{ 50 }\] and that of encountering a black one is \[P _{b}=\frac{ 10 }{ 50 }\].
- The number of black balls in W could be = to the number of white balls in B, because possibly, 10 white balls could be put in box B, hence having 10Black in W and 10 White in B.
- The number of black balls in W can be more than the white balls in B after ten picks, if for instance 7 black were picked and 3 white were picked.
- Similarly, the aforementioned explanation works for the 3 case.
- The last alternative would be incorrect.

- anonymous

@rvc?

- rvc

sorry to keep u waiting i was afk
gtg
i appreciate ur help ;)

- mathmath333

Wow jim thopson's answer was amazing!

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