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rvc

  • one year ago

If aN implies S eF implies I gH implies M then nS implies ?

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  1. rvc
    • one year ago
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    The options are : 1)T 2)A 3)L 4)K

  2. rvc
    • one year ago
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    @ikram002p @Loser66

  3. rvc
    • one year ago
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    what is the logic?

  4. Loser66
    • one year ago
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    I am trying but not find out yet. ha!!

  5. Loser66
    • one year ago
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    I don't know!! I am sorry.

  6. rvc
    • one year ago
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    okay thanks for trying @Loser66

  7. princeharryyy
    • one year ago
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    eF implies I or L @rvc

  8. rvc
    • one year ago
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    I

  9. princeharryyy
    • one year ago
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    ok! let me ntry n find the connection.

  10. anonymous
    • one year ago
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    I think its K... I have a weird reason... is the answer known to you @rvc?

  11. rvc
    • one year ago
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    no i dont know the ans

  12. mathmath333
    • one year ago
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    What is the source of the question is it related to mathamatics .

  13. rvc
    • one year ago
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    yeah

  14. Loser66
    • one year ago
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    @mathmath333 it's called encryption maths

  15. mathmath333
    • one year ago
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    ok i see @Loser66

  16. freckles
    • one year ago
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    hey @rvc can I asked where this question came from?

  17. rvc
    • one year ago
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    This question is from NET Exam

  18. freckles
    • one year ago
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    Can I find that exam on the internet?

  19. rvc
    • one year ago
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    i dont know you may please try :)

  20. freckles
    • one year ago
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    so loser said it had something to do with encryption is there anything else you can tell me about this problem? Like there are all kinds of encryption systems... I guess this is a mathematics Net exam?

  21. rvc
    • one year ago
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    ah The question doesnt give any more information

  22. Empty
    • one year ago
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    Since aN implies S then backwards we have while changing the case to match: nS implies A. A is an answer choice, but this is a super weak reason for this to be the answer haha.

  23. freckles
    • one year ago
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    if nothing else was given how did loser know this had something to do with encryption?

  24. dan815
    • one year ago
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    |dw:1434952460774:dw|

  25. freckles
    • one year ago
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    all I did 1-26 for capital letters and 27-52 for lower case letters didn't find a pattern

  26. rvc
    • one year ago
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    :/

  27. dan815
    • one year ago
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    you..

  28. dan815
    • one year ago
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    why are u still here, family reunion boy

  29. Empty
    • one year ago
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    I was considering the rotational and reflectional symmetries of the letters and also considering their placement on a keyboard to see if there was a relationship, also vowels and consonants, still nothing. I don't leave until tomorrow dan lol

  30. Empty
    • one year ago
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    The only patterns I'm seeing are: lower case, upper case implies upper case and the answer choices spell out TALK.

  31. Empty
    • one year ago
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    Honestly if someone can legit figure this out in a way that's reasonable, I'll give you a medal + fan. lol

  32. rvc
    • one year ago
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    |dw:1434952862606:dw|

  33. dan815
    • one year ago
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    |dw:1434952911473:dw|

  34. Empty
    • one year ago
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    |dw:1434952901247:dw|

  35. dan815
    • one year ago
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    |dw:1434952934158:dw|

  36. rvc
    • one year ago
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    by so on i meant the full question because its hard to draw here @Empty

  37. Empty
    • one year ago
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    @dan815 do you mean this? http://prntscr.com/7jtxyu

  38. dan815
    • one year ago
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    the 5,6 =>9 and 7,8=>13 makes me think maybe there is apttern with numbers its like +2 for each number ?

  39. Empty
    • one year ago
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    Ok what's the sequence: 1,1,2,...?

  40. freckles
    • one year ago
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    do i get to answer that? :p or should rvc get to answer that @empty ?

  41. dan815
    • one year ago
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    i am not answering these questions, its never what it it looks like with u

  42. dan815
    • one year ago
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    lol

  43. Empty
    • one year ago
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    No this is open for anyone, answer away @freckles it's all yours :)

  44. freckles
    • one year ago
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    it looks like the first few terms of the fibnocci sequence you have written

  45. Empty
    • one year ago
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    Sorry that's not it try again

  46. dan815
    • one year ago
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    lol

  47. dan815
    • one year ago
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    1,1,2,2

  48. Empty
    • one year ago
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    Sorry the next term in the sequence is http://prntscr.com/7jtyvr. I'll give you a medal if you can write the function for the nth term, it's a simple expression

  49. dan815
    • one year ago
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    1,1,2,3,4,5

  50. rvc
    • one year ago
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    im confused

  51. Empty
    • one year ago
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    Whoops I had put a period at the end. http://prntscr.com/7jtyvr

  52. Empty
    • one year ago
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    @rvc This problem is impossible and I'm giving an example of a problem that looks just as simple that's equally as nonsensical and ambiguous.

  53. freckles
    • one year ago
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    @rvc would it be against any copyright rules or laws or whatever if you posted a picture of that question? Or like even better and if not too much trouble can you copy and send the whole exam thing ? I still don't get it. Maybe I can get a better feel for the problem based on the other questions.

  54. Empty
    • one year ago
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    By the way the formula for the nth term of my series is starting from 0, 1,2,3, etc... f(n)=n!!!!!

  55. Empty
    • one year ago
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    The answer seems to be T because it's the only way to maintain the pattern that the letters are always in alphabetical order.

  56. rvc
    • one year ago
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    oh okay please wait

  57. freckles
    • one year ago
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    That is a interesting answer @Empty and is probably more possible then the other but I don't know :p

  58. Empty
    • one year ago
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    Yeah see this is garbage

  59. rvc
    • one year ago
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  60. rvc
    • one year ago
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    The 14th question

  61. freckles
    • one year ago
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    well cookie! I'm still lost. I will have to think more about this question tomorrow because it is 1:27 AM. Sorry @rvc . :(

  62. rvc
    • one year ago
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    thank you so much for your effort @freckles

  63. dan815
    • one year ago
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    so are we agreeing on T

  64. Empty
    • one year ago
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    The T argument is just as good as the A argument. I'm not convinced the alphabetical order isn't just some coincidence because there's no sort of equal spacing between the letters at all.

  65. rvc
    • one year ago
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    so T is the ans?

  66. Empty
    • one year ago
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    That's not what I'm saying at all

  67. Empty
    • one year ago
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    I'm saying this is a terrible problem and I feel bad that this is a test question.

  68. ganeshie8
    • one year ago
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    lol #14 and #15 look more like reasoning problems which everybody hates because they are a bit ambiguous and not so regular mathy

  69. rvc
    • one year ago
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    15th is easy

  70. ganeshie8
    • one year ago
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    im actually trying both #14 and #15 in parallel w/o any success whats the solution for #15 ?

  71. rvc
    • one year ago
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    15th : |dw:1434956874159:dw|

  72. ganeshie8
    • one year ago
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    that's so cool !

  73. rvc
    • one year ago
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    yep but the 14th and 16th is not cool lol what about 12th?

  74. ganeshie8
    • one year ago
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    #12 should be number of black marbles in W = number of white marbles in B because whatever the new white marbles in B, they have come from the jar W

  75. rvc
    • one year ago
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    |dw:1434957539577:dw|

  76. rvc
    • one year ago
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    |dw:1434957746502:dw|

  77. ganeshie8
    • one year ago
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    In 3rd case, notice that you have "40 white" and "10 black" marbles in jarW. Suppose you randomly pick "x white" and "10-x black" marbles from jarW and put them in jarB. Then the number of black marbles left behind in jarW would be ?

  78. jim_thompson5910
    • one year ago
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    #14 This is my guess. I could be way off. aN => S eF => I gH => M flip the letters in the first part to get Na => S Fe => I Hg => M we have Na, Fe, Hg. All code names for elements on the periodic table Na = Sodium which starts with an S. So that explains Na => S Fe = Iron, so that explains Fe => I Hg = Mercury, explains Hg => M So nS turns into Sn which is Tin So I'm thinking that Sn => T which means nS => T It's the only thing that comes to mind which makes sense because it fits, but at the same time, this is chemistry material (which doesn't fit in a math test).

  79. rvc
    • one year ago
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    hmmm idk @ganeshie8 black marble will be 10-x =y

  80. rvc
    • one year ago
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    wow congrats!!!! @jim_thompson5910 Thank youuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

  81. ganeshie8
    • one year ago
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    wow @jim_thompson5910 that should be it xD

  82. jim_thompson5910
    • one year ago
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    it might be that or something way different

  83. rvc
    • one year ago
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    you proved it

  84. rvc
    • one year ago
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    what about the rest :/

  85. ganeshie8
    • one year ago
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    For #16, you may use 30-60-90 triangle |dw:1434959042367:dw|

  86. rvc
    • one year ago
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    what should i do next @ganeshie8 ?

  87. ganeshie8
    • one year ago
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    use 30-60-90 triangle or directly go for trig to find the lengths of other sides in that right triangle in terms of R

  88. rvc
    • one year ago
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    |dw:1434959598398:dw|

  89. rvc
    • one year ago
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    @ganeshie8 please help

  90. jim_thompson5910
    • one year ago
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    @rvc, do you see how point C is R units away from A? The question is pretty much answered at this point

  91. rvc
    • one year ago
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    yep i found that :) thank you so much @jim_thompson5910

  92. rvc
    • one year ago
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    @jim_thompson5910 what about the 12th one?

  93. rvc
    • one year ago
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    @mukushla

  94. anonymous
    • one year ago
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    So exercise 12 is about probability...

  95. rvc
    • one year ago
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    yep

  96. anonymous
    • one year ago
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    hi, I can't understand the question

  97. rvc
    • one year ago
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    :/

  98. rvc
    • one year ago
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    which one ? the 12th one? did you see that file?

  99. anonymous
    • one year ago
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    Alright! Let the number of white balls in Box W be 40 whites and that in box B, 40 black balls. After ten black balls being transferred to box W, the probability of encountering a white ball at any pick is \[P _{w}=\frac{ 40 }{ 50 }\] and that of encountering a black one is \[P _{b}=\frac{ 10 }{ 50 }\]. - The number of black balls in W could be = to the number of white balls in B, because possibly, 10 white balls could be put in box B, hence having 10Black in W and 10 White in B. - The number of black balls in W can be more than the white balls in B after ten picks, if for instance 7 black were picked and 3 white were picked. - Similarly, the aforementioned explanation works for the 3 case. - The last alternative would be incorrect.

  100. anonymous
    • one year ago
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    @rvc?

  101. rvc
    • one year ago
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    sorry to keep u waiting i was afk gtg i appreciate ur help ;)

  102. mathmath333
    • one year ago
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    Wow jim thopson's answer was amazing!

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