anonymous
  • anonymous
A 250.0 g metal block absorbs 7.849 × 10^3 J of heat to raise its temperature by 35.0 K. What is the substance? ***How can I explain and show the work for this? will attach the corresponding table inside!! thanks!! @michele_laino :)
Physics
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Michele_Laino
  • Michele_Laino
here we have to compute the specific heat, as follows: \[\large c = \frac{1}{m}\frac{Q}{{\Delta t}} = \frac{1}{{0.25}}\frac{{7.849 \times {{10}^3}}}{{35}} = ...J/(Kg \times ^\circ K)\]
anonymous
  • anonymous
ok! so we get 897.0285 ?

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Michele_Laino
  • Michele_Laino
yes!
Michele_Laino
  • Michele_Laino
now, look at your table
anonymous
  • anonymous
yay!! so this means our substance is aluminum?
Michele_Laino
  • Michele_Laino
that's right!
anonymous
  • anonymous
yay! thank you !! so that is it for this problem? :O
Michele_Laino
  • Michele_Laino
yes! we have finished!
anonymous
  • anonymous
yay!! thank you!! i will post the next one now:)
Michele_Laino
  • Michele_Laino
:) ok!

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