## anonymous one year ago A 250.0 g metal block absorbs 7.849 × 10^3 J of heat to raise its temperature by 35.0 K. What is the substance? ***How can I explain and show the work for this? will attach the corresponding table inside!! thanks!! @michele_laino :)

1. anonymous

2. Michele_Laino

here we have to compute the specific heat, as follows: $\large c = \frac{1}{m}\frac{Q}{{\Delta t}} = \frac{1}{{0.25}}\frac{{7.849 \times {{10}^3}}}{{35}} = ...J/(Kg \times ^\circ K)$

3. anonymous

ok! so we get 897.0285 ?

4. Michele_Laino

yes!

5. Michele_Laino

6. anonymous

yay!! so this means our substance is aluminum?

7. Michele_Laino

that's right!

8. anonymous

yay! thank you !! so that is it for this problem? :O

9. Michele_Laino

yes! we have finished!

10. anonymous

yay!! thank you!! i will post the next one now:)

11. Michele_Laino

:) ok!