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anonymous

  • one year ago

A 250.0 g metal block absorbs 7.849 × 10^3 J of heat to raise its temperature by 35.0 K. What is the substance? ***How can I explain and show the work for this? will attach the corresponding table inside!! thanks!! @michele_laino :)

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  1. anonymous
    • one year ago
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  2. Michele_Laino
    • one year ago
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    here we have to compute the specific heat, as follows: \[\large c = \frac{1}{m}\frac{Q}{{\Delta t}} = \frac{1}{{0.25}}\frac{{7.849 \times {{10}^3}}}{{35}} = ...J/(Kg \times ^\circ K)\]

  3. anonymous
    • one year ago
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    ok! so we get 897.0285 ?

  4. Michele_Laino
    • one year ago
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    yes!

  5. Michele_Laino
    • one year ago
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    now, look at your table

  6. anonymous
    • one year ago
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    yay!! so this means our substance is aluminum?

  7. Michele_Laino
    • one year ago
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    that's right!

  8. anonymous
    • one year ago
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    yay! thank you !! so that is it for this problem? :O

  9. Michele_Laino
    • one year ago
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    yes! we have finished!

  10. anonymous
    • one year ago
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    yay!! thank you!! i will post the next one now:)

  11. Michele_Laino
    • one year ago
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    :) ok!

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