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anonymous
 one year ago
A 250.0 g metal block absorbs 7.849 × 10^3 J of heat to raise its temperature by 35.0 K. What is the substance?
***How can I explain and show the work for this?
will attach the corresponding table inside!! thanks!! @michele_laino :)
anonymous
 one year ago
A 250.0 g metal block absorbs 7.849 × 10^3 J of heat to raise its temperature by 35.0 K. What is the substance? ***How can I explain and show the work for this? will attach the corresponding table inside!! thanks!! @michele_laino :)

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Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1here we have to compute the specific heat, as follows: \[\large c = \frac{1}{m}\frac{Q}{{\Delta t}} = \frac{1}{{0.25}}\frac{{7.849 \times {{10}^3}}}{{35}} = ...J/(Kg \times ^\circ K)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok! so we get 897.0285 ?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1now, look at your table

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yay!! so this means our substance is aluminum?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yay! thank you !! so that is it for this problem? :O

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1yes! we have finished!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yay!! thank you!! i will post the next one now:)
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