anonymous one year ago A 12.0 V battery is hooked up with three resistors (R1, R2, and R3) in parallel with resistances of 2.5 Ω, 7.0 Ω, and 15.0 Ω, respectively. Part 1: Draw a labeled circuit diagram for the circuit described using correct symbols. Part 2: Calculate the equivalent resistance. Part 3: Calculate the current passing through each resistor in the circuit. ***How do I do this?

1. Michele_Laino

the requested circuit is: |dw:1434903805092:dw|

2. anonymous

so that is the drawing?

3. Michele_Laino

|dw:1434903890518:dw|

4. Michele_Laino

yes! I think so!

5. anonymous

ok yay!! so that is it for part 1?

6. Michele_Laino

yes!

7. anonymous

ookie yay!! and so now we go to part 2? how do we do that? :/

8. Michele_Laino

part #2 the equivalent resistance is: $\Large \begin{gathered} {R_{EQUIVALENT}} = \frac{1}{{\frac{1}{{{R_1}}} + \frac{1}{{{R_2}}} + \frac{1}{{{R_3}}}}} = \hfill \\ \hfill \\ = \frac{1}{{\frac{1}{{2.5}} + \frac{1}{7} + \frac{1}{{15}}}} = ...Ohm \hfill \\ \end{gathered}$

9. anonymous

ok! so we get 1.640625?

10. Michele_Laino

that's right!

11. anonymous

yay so that is our equivalent resistance? :O

12. Michele_Laino

it is 1.64 ohms

13. anonymous

ooh okie yay!! so onto part 3!

14. Michele_Laino

the requested currents are: $\Large \begin{gathered} {I_1} = \frac{{12}}{{2.5}} = ...Amps \hfill \\ \hfill \\ {I_2} = \frac{{12}}{7} = ...Amps \hfill \\ \hfill \\ {I_3} = \frac{{12}}{{15}} = ...Amps \hfill \\ \end{gathered}$

15. Michele_Laino

|dw:1434904298434:dw|

16. anonymous

ok! we get these values? 4.8 1.71 0.8 ?

17. Michele_Laino

correct!

18. anonymous

yay!! and so we are finished with this problem? :O

19. Michele_Laino

yes!

20. anonymous

ooh yay!! thank you!!:) onto the next!!

21. Michele_Laino

:) ok!