anonymous
  • anonymous
A block and tackle is used to raise a 72.0 N crate 12.3 m from the loading dock to the ship. This requires a force of 25.0 N to be applied by the longshoreman. Part 1: What is the mechanical advantage of the block and tackle? Part 2: How much rope must be pulled? Note: Assume that IMA = MA. Part 3: The longshoremen have only a 40 m rope that they are told not to cut. They use this for the block and tackle. How does this affect the efficiency of the block and tackle? **how do we solve these? :/ thanks @Michele_Laino !!:)
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Michele_Laino
  • Michele_Laino
part 1 the requested advantage is given by the subsequent ratio: \[\large R = \frac{{72}}{{25}}\]
anonymous
  • anonymous
oh okay! so we get 2.88 is the requested mechanical advantage?
Michele_Laino
  • Michele_Laino
yes! Whereas the efficiency E, of our machine, is: \[\Large E = \frac{{25}}{{72}} = ...\]

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anonymous
  • anonymous
ohh okay! it is 0.347222....
Michele_Laino
  • Michele_Laino
no, it is an additional information only. Our answer, to part 1 is 2.88
anonymous
  • anonymous
oh ok! so we do not need to include the efficiency? just the 2.88 mechanical advantage?
Michele_Laino
  • Michele_Laino
yes!
anonymous
  • anonymous
okie! so onto part 2!
Michele_Laino
  • Michele_Laino
for part #2, if I call with L the length of the pulled rope, then we can write: \[\large 72 \times 12.3 = 25 \times L\]
Michele_Laino
  • Michele_Laino
so we have: \[\Large L = \frac{{72 \times 12.3}}{{25}} = ...meters\]
anonymous
  • anonymous
we get 35.424!
Michele_Laino
  • Michele_Laino
correct!
anonymous
  • anonymous
so is that the amount of how much rope must be pulled? 35.424 m?
Michele_Laino
  • Michele_Laino
yes!
anonymous
  • anonymous
ok! yay!! so onto part 3?
Michele_Laino
  • Michele_Laino
if we have to pull 40 meters of rope, then the force F applied by the longshoremen, is: \[\Large F = \frac{{72 \times 12.3}}{{40}} = ...Newtons\]
anonymous
  • anonymous
ok! so we get 22.14 Newtons! is that our solution for part 3?
anonymous
  • anonymous
oh wait, that is just the force, right? how can we find the efficiency?
Michele_Laino
  • Michele_Laino
the new advantage is: \[\Large R = \frac{{72}}{{22.14}} = ...\]
anonymous
  • anonymous
or how can we find how it affects the efficiency?
Michele_Laino
  • Michele_Laino
whereas the new efficiency, is: \[\Large E = \frac{{22.14}}{{72}} = ...\]
Michele_Laino
  • Michele_Laino
I think that your problem asks for efficiency, also in part #1
anonymous
  • anonymous
ok! so we get 0.3075 is the efficiency? and i think we don't need it for part 1? since it asks for mechanical advantage only? or do we need to include the efficiency we calculated earlier for part 1?
Michele_Laino
  • Michele_Laino
so the answer to part #1 is: \[\Large E = \frac{{25}}{{72}} \cong 0.35\]
Michele_Laino
  • Michele_Laino
that's right! the new efficiency is: \[\Large E = \frac{{22.14}}{{72}} \cong 0.31\]
Michele_Laino
  • Michele_Laino
namely the efficiency will decrease
anonymous
  • anonymous
yes:) and yay!! so that is how it affects efficiency? it will decrease?
Michele_Laino
  • Michele_Laino
yes! correct!
anonymous
  • anonymous
yay! thanks!! so we are done?
Michele_Laino
  • Michele_Laino
yes! we have finished!
anonymous
  • anonymous
yay!! ok! onto the next!!:)
anonymous
  • anonymous
thank you!!
Michele_Laino
  • Michele_Laino
:) :)

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