A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
A 2.4 cm object is 15.0 cm to the left of a convex lens with a focal length of +5.0 cm.
Part 1: Draw a ray diagram of the setup showing the location of the image.
Part 2: Calculate the distance of the image from the lens.
Part 3: What size is the image and is it upright or inverted?
anonymous
 one year ago
A 2.4 cm object is 15.0 cm to the left of a convex lens with a focal length of +5.0 cm. Part 1: Draw a ray diagram of the setup showing the location of the image. Part 2: Calculate the distance of the image from the lens. Part 3: What size is the image and is it upright or inverted?

This Question is Closed

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1here is the drawing of your problem: dw:1434906888314:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1here we have to apply this formula: \[\Large \frac{1}{p} + \frac{1}{q} = \frac{1}{f}\] where p= 15 cm f= 5 cm please solve for q

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok! 1/15 + 1/q = 1/5 1/q = 3 q=1/3 ?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we have: \[\Large q = \frac{{fp}}{{p  f}} = \frac{{5 \times 15}}{{15  5}} = ...cm\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh oops so we get 75 / 10 = 7.5 cm ?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1now, from my drawing, we get that the image is inverted

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay! so part 2 is that it is 7.5 cm away from the lens? and part 3 is that it is inverted?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1yes! nevertheless we have to determine the dimension of the image

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes! we have to calculate the size, too.. how do we do that?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we can use the similarity property of these triangles: dw:1434907503742:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so we can write this proportion: \[\Large 2.4:15 = x:7.5\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1or, applying the fundamental property of proportion: \[\Large x = \frac{{2.4 \times 7.5}}{{15}} = ...cm\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we get 1.2 cm? that is the size of the image?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yay! so we are finished with this? :O

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1yes! we have finished! :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yay!! okay, onto the last one!!:) thank you1!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.