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anonymous

  • one year ago

Question inside!:)

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  1. anonymous
    • one year ago
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    |dw:1434907802971:dw|

  2. Michele_Laino
    • one year ago
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    as we can see from your reaction, the mass number will decrease by four units as we go from left side to the right side. Furthermore, the atomic number will decrease by 2 units as we go from left side to right side, so the complete reaction is: |dw:1434908046133:dw| namely it is \alpha particle

  3. anonymous
    • one year ago
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    so it would be the full equation.. continued off like this? ..Np + alpha particle 4 2

  4. anonymous
    • one year ago
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    that would make it the complete equation?

  5. Michele_Laino
    • one year ago
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    that's right! Please see my tutorial: http://openstudy.com/study#/updates/5573f338e4b0bffbfeff3829

  6. anonymous
    • one year ago
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    ooh okie yay! thanks!! :) so that is it for part 1?

  7. Michele_Laino
    • one year ago
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    it is for part #2 too since the radiation involved is the "alpha radiation"

  8. anonymous
    • one year ago
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    okie! yay! what about part 3? :)

  9. Michele_Laino
    • one year ago
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    the involved alpha particle is coming from the nucleus of: \[\Large {}_{95}^{241}Am\]

  10. anonymous
    • one year ago
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    ohhh okie Yay!! so this problem is complete? :O

  11. Michele_Laino
    • one year ago
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    yes! we have finished!

  12. anonymous
    • one year ago
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    yay!! thanks so much!!!:D

  13. Michele_Laino
    • one year ago
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    :) :)

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