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@mathmate Hello. This one is tough one for me! PLease help
2 solutions... x = 3 and x = 2... do u need a detailed explanation as before?
Oh yes please! If anyone who have different idea please let me know
hold on a minute
Find common denominator, subtract, and cross multiply to give the quadratic equation x^2-5x+6=0, or (x-3)(x-3)=0. However, check the two solutions x=2 or x=3 by substituting into the original equation. \(One\) of them gives a zero for denominator, hence is not a solution.
yes - the one that is not a solution is called extraneous.
So I'm correct?
only 3 is a solution... I was wrong; a bit!
So, can you tell me which one is correct? @welshfella @mathmate
now plugging 2 into the original equation leads to infinity - infinity; which is absurd. but 3 gives a correct solution. check for it in the same way as for 2
there's an error in your last line multiplying through by (x-2)(x+2) gives (x-2)(x+2) on right hand side
@KittyT You have to do some work too! lol Read through my response and do some checking, and you will find your answer AND also understand why. OR read the last posts of @wrik003 to find the answer! Good luck!
it should be 5(x + 2) - 20 = x^2 - 4
I got 2 solutions....
what are they/
x=3 and x=2
u are stating something as exact as mine @welshfella. the only difference being that u have cross-multiplied x^2 -4 with 1! Hope u get it!
@KittyT check my 2nd last post & u shall find the answer
is it your workout?
I think there's one solution which is x=3
yes... whose else's workout could it be? my local time right now is 23:42! how do u suppose I'll get external; help?!
So it's right?
yes... my workout is correct... as verified my @mathmate.
So my final answer is 1 solution only!