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AmTran_Bus
 one year ago
Integration help
AmTran_Bus
 one year ago
Integration help

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AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0dw:1434926190793:dw

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0dw:1434926209378:dw

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0\[uv\int\limits vdu\]

idku
 one year ago
Best ResponseYou've already chosen the best response.0more steps, but less mess and confusion. u=3t then by parts

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0\[t \frac{ e ^{3t} }{ 3 }\int\limits \frac{ e ^{3t} }{ 3 }dt\]

idku
 one year ago
Best ResponseYou've already chosen the best response.0u can do a power series too, if you would like.

idku
 one year ago
Best ResponseYou've already chosen the best response.0anyway, u got people here....

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0This is what I'm doing right now, this is the IBP section.

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0So do a U sub first? ok.

idku
 one year ago
Best ResponseYou've already chosen the best response.0du=(3)dx > du/(3) = dx

idku
 one year ago
Best ResponseYou've already chosen the best response.0(don't forget to sub back the x)

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0So do I need to say dt = du/3?

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0dw:1434926595047:dw

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Supposed to be a neg there... Then IBP?

idku
 one year ago
Best ResponseYou've already chosen the best response.0you can also say, \[\Large \int\limits_{ }^{ }te^{3t}dt\] \[\Large \frac{1}{9}\int\limits_{ }^{ }3(3t)e^{3t}dt\] (i used a magic 1) \[u=3t~~~du=3dt\] \[\Large \frac{1}{9}\int\limits_{ }^{ }\color{blue}{3}\color{red}{(3t)}e^{\color{red}{3t}}\color{blue}{dt}\]

idku
 one year ago
Best ResponseYou've already chosen the best response.0the blue part is the part that gets replaced by du. the red  each thing is a u

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Where is the 1/9 from? I would like to do it the way I have just started.

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0dw:1434926879794:dw

idku
 one year ago
Best ResponseYou've already chosen the best response.0i multiply times 3 times 3 and times 1/9

idku
 one year ago
Best ResponseYou've already chosen the best response.0and write that all out, to have my u's

idku
 one year ago
Best ResponseYou've already chosen the best response.0u don't have to do it like this. I am preparing my integral for the sub. U also can do the sub and rearrange then.

idku
 one year ago
Best ResponseYou've already chosen the best response.0\[\Large \frac{1}{9}\int\limits\limits_{ }^{ }3(3t)e^{3t}dt\] (the only thing is like this) no 9 on bottom, it is positive

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Refer to the attachment from WolframAlpha.

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Thanks...but I really want to work it from scratch on my own.

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0dw:1434927052945:dw

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0If it were me, I'd do IBP first.dw:1434927094434:dw

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0dw:1434927121584:dw

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0At this point, what do I do?

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Well, this is no help. Closed.

Zale101
 one year ago
Best ResponseYou've already chosen the best response.1\[\Large \int\limits_{}^{}te^{3t}dt\] u=t and du=dt dv=e^(3t) and v=(1/3)e^(3t) Now, use IBP \(uv\int\limits_{}^{}vdu\) \(\large =\frac{1}{3}te^{3t}\int\limits_{}^{}(\frac{1}{3})e^{3t}dt\) \(\large =\frac{1}{3}te^{3t}+\frac{1}{3}\int\limits_{}^{}e^{3t}dt=\frac{1}{3}te^{3t}\frac{1}{9}e^{3t}+c\)
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