anonymous
  • anonymous
Need help Consider the quadratic equation y^2-y=6. What is the error with the solution below? y^2-y=6 y(y-1)=6 y=6 or y-1=6 y=6 or y=7 (6,7) A. The solution is correct. B. in y^2-y=6, y^2 should have been factored out instead of y C. in y^2-y=6, 6 should have been subtracted on both sides first. D. Instead of y = 6, it should have been y = –6.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
try c
welshfella
  • welshfella
the third line is incorrect C is the correct option
anonymous
  • anonymous
\[y^2-y-6=0\]

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anonymous
  • anonymous
Thanks

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