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melstutes

  • one year ago

Given: AB .BE = CB . BD Prove: Triangle ABC is similar to triangle DBE

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  1. melstutes
    • one year ago
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  2. melstutes
    • one year ago
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    Please help me

  3. melstutes
    • one year ago
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    Thanks for trying

  4. Mertsj
    • one year ago
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    I don't understand the given. Could you please type it correctly?

  5. melstutes
    • one year ago
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  6. melstutes
    • one year ago
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    I have not had Geometry, I watched a video explaining AA SAS and SS

  7. Mertsj
    • one year ago
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    \[(AB)(BE)=(CB)(BD)\] \[\frac{(AB)(BE)}{(BE)(BD)}=\frac{(CB)(BD)}{(BE)(BD)}\] \[\frac{(AB)}{(BD)}=\frac{(CB)}{(BE)}\]

  8. Mertsj
    • one year ago
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    So now we have established that corresponding sides have equal ratios.

  9. Mertsj
    • one year ago
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    Now use the fact that vertical angles are congruent and you have SAS similarity.

  10. melstutes
    • one year ago
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    I knew about vertical angles

  11. melstutes
    • one year ago
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    thanks

  12. Mertsj
    • one year ago
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    yw

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