In the diagram, points D and E are marked by drawing arcs of equal size centered at B such that the arcs intersect BA−→ and BC−→. Then, intersecting arcs of equal size are drawn centered at points D and E. Point P is located at the intersection of these arcs.

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The construction is of the angle bisector so angle ABP is 32 and angle ABC is 64

Okay, but the second part?..

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