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anonymous
 one year ago
In the diagram, points D and E are marked by drawing arcs of equal size centered at B such that the arcs intersect BA−→ and BC−→. Then, intersecting arcs of equal size are drawn centered at points D and E. Point P is located at the intersection of these arcs.
anonymous
 one year ago
In the diagram, points D and E are marked by drawing arcs of equal size centered at B such that the arcs intersect BA−→ and BC−→. Then, intersecting arcs of equal size are drawn centered at points D and E. Point P is located at the intersection of these arcs.

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Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2The construction is of the angle bisector so angle ABP is 32 and angle ABC is 64

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, but the second part?..

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2What is the second part? I don't see a second part.

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2When someone tries to help you, would it be too much trouble for you to read what they have written?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I just do not understand it...

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2so angle ABP is 32 and angle ABC is 64

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I did not realize that is what you were saying. I feel very stupid. I apologize.
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