anonymous
  • anonymous
In the diagram, points D and E are marked by drawing arcs of equal size centered at B such that the arcs intersect BA−→ and BC−→. Then, intersecting arcs of equal size are drawn centered at points D and E. Point P is located at the intersection of these arcs.
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
Mertsj
  • Mertsj
The construction is of the angle bisector so angle ABP is 32 and angle ABC is 64
anonymous
  • anonymous
Okay, but the second part?..

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Mertsj
  • Mertsj
What is the second part? I don't see a second part.
anonymous
  • anonymous
This.
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Mertsj
  • Mertsj
When someone tries to help you, would it be too much trouble for you to read what they have written?
anonymous
  • anonymous
I just do not understand it...
Mertsj
  • Mertsj
so angle ABP is 32 and angle ABC is 64
anonymous
  • anonymous
OH.
anonymous
  • anonymous
I did not realize that is what you were saying. I feel very stupid. I apologize.
Mertsj
  • Mertsj
np

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