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anonymous

  • one year ago

In the diagram, points D and E are marked by drawing arcs of equal size centered at B such that the arcs intersect BA−→ and BC−→. Then, intersecting arcs of equal size are drawn centered at points D and E. Point P is located at the intersection of these arcs.

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  1. anonymous
    • one year ago
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  2. Mertsj
    • one year ago
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    The construction is of the angle bisector so angle ABP is 32 and angle ABC is 64

  3. anonymous
    • one year ago
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    Okay, but the second part?..

  4. Mertsj
    • one year ago
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    What is the second part? I don't see a second part.

  5. anonymous
    • one year ago
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    This.

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  6. Mertsj
    • one year ago
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    When someone tries to help you, would it be too much trouble for you to read what they have written?

  7. anonymous
    • one year ago
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    I just do not understand it...

  8. Mertsj
    • one year ago
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    so angle ABP is 32 and angle ABC is 64

  9. anonymous
    • one year ago
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    OH.

  10. anonymous
    • one year ago
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    I did not realize that is what you were saying. I feel very stupid. I apologize.

  11. Mertsj
    • one year ago
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    np

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