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\[2x^3y + 18xy - 10x^2y - 90y\] right?

common factor? each term has a \(2y\) in it
factor it out first

yes that's correct

i got 2y(9x^3-5x^2-45) for A. is that correct? @satellite73

looks like you are missing something

\[2x^3y + 18xy - 10x^2y - 90y\] factor out the \(2y\) and get
\[2y(x^3+9x-5x^2-45)\]

then you can factor further, but how you are supposed to do that i am not sure

final factored form is \[2 y(x-5) (x^2+9)\]

as for 3) there is only one way to factor a polynomial, so nothing would change

I completed it. Thanks for your help! I forgot to do that last step @satellite73