An expression is shown below: 2x3y + 18xy - 10x2y - 90y 1. Rewrite the expression so that the GCF is factored completely. 2. Rewrite the expression completely factored. Show the steps of your work. 3. If the two middle terms were switched so that the expression became 2x3y - 10x2y + 18xy - 90y, would the factored expression no longer be equivalent to your answer in part 2? Explain your reasoning.

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An expression is shown below: 2x3y + 18xy - 10x2y - 90y 1. Rewrite the expression so that the GCF is factored completely. 2. Rewrite the expression completely factored. Show the steps of your work. 3. If the two middle terms were switched so that the expression became 2x3y - 10x2y + 18xy - 90y, would the factored expression no longer be equivalent to your answer in part 2? Explain your reasoning.

Mathematics
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\[2x^3y + 18xy - 10x^2y - 90y\] right?
common factor? each term has a \(2y\) in it factor it out first
yes that's correct

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i got 2y(9x^3-5x^2-45) for A. is that correct? @satellite73
looks like you are missing something
\[2x^3y + 18xy - 10x^2y - 90y\] factor out the \(2y\) and get \[2y(x^3+9x-5x^2-45)\]
then you can factor further, but how you are supposed to do that i am not sure
final factored form is \[2 y(x-5) (x^2+9)\]
maybe we can write \[x^3-5x^2+9x-45\] as \[x^2(x-5)+9(x-5)\] then we see a common factor of \(x-5\) so factor further as \[(x^2-9)(x-5)\]
as for 3) there is only one way to factor a polynomial, so nothing would change
I completed it. Thanks for your help! I forgot to do that last step @satellite73

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