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anonymous

  • one year ago

The slope of the line below is 5. Write the point-slope equation for the line using the coordinates of the labeled point. Do not include spaces in your answer. http://media.apexlearning.com/Images/200707/01/43234416-fd7e-4dd9-9a58-5a1964123363.gif

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  1. anonymous
    • one year ago
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    please help!

  2. anonymous
    • one year ago
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    thank you

  3. Astrophysics
    • one year ago
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    Oh so you dont want an explanation?

  4. anonymous
    • one year ago
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    yes i do

  5. jim_thompson5910
    • one year ago
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    y=5x+12 isn't the answer

  6. anonymous
    • one year ago
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    do any of you know how to help me with these ? i don't understand - Which point lies on the line described by the equation below? y - 3 = 2(x + 5) A. (3, 17) B. (4, 21) C. (4, 18) D. (3, -3) E. (-2, 13) F. (-1, 9)

  7. Astrophysics
    • one year ago
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    Ok, so |dw:1434945650832:dw| so we want it in the equation of a line form (y=mx+b) to do this we can do the following: We are given a point (x,y) which we will treat as

  8. Astrophysics
    • one year ago
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    \[(x_1, y_1) \implies (-1,3)\] since we are given all this information we can go directly to using point - slope form: \[y-y _{1}=m(x-x _{1})\] we leave y and x alone, and plug in points (x1,y1) as presented above. So we have the following \[y-(-1) = m(x-3)\] now we know that our slope is 5 so we plug that in for m since m represents the slope in y = mx+b form, and b is the y - intercept. Doing some algebra with the above equation we get \[y+1 = 5x-15 \implies y=5x-16\]

  9. triciaal
    • one year ago
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    |dw:1434945926919:dw|

  10. Astrophysics
    • one year ago
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    Oh I put the coordinates backwards :P

  11. Astrophysics
    • one year ago
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    It should be \[y-3 = 5x+5 \implies y = 5x+8\]

  12. Astrophysics
    • one year ago
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    For your second question, set your equation up in y = mx+b form and graph it out and see if the coordinates are on the line (this will help you visualize it).

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