## anonymous one year ago An object is launched at 20 m/s from a height of 65 m. The equation for the height (h) in terms of time (t) is given by h(t) = -4.9t2 + 20t + 65. What is the object's maximum height?

1. Zale101

You can find the maximum height of the object from the vertex. Do you remember how to find the vertex of an equation? |dw:1434946064036:dw|

2. anonymous

i really don't know i'm sorry i'm so bad at math

3. Zale101

You can either complete the square or find the vertex by this formula $$\Large Vertex=(h,k)=(\LARGE-\frac{b}{2a},c-\frac{b^2}{4a})$$ Where ax^2+bx+c=0 is the standard form -4.9t^2 + 20t + 65=0 a=-4.9 b=20 c=65