Two vehicles collide and stick together. After the collision, their combined y-momentum is 2.40 x 10^4 kilogram meters/second, and their x-momentum is 7.00 x 10^4 kilogram meters/second. What is the angle of the motion of the two vehicles, with respect to the x-axis?
Could someone please assist?
EDIT:
Okay, so I tried myself and here's what I did:
2.40 x 10^4 * 7.00 x 10^4 = 168 = 16.8 degrees
Not sure if right, anyone want to confirm?

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- Astrophysics

I'm not sure what you're doing, but momentum is \[\vec p = m \vec v\] you should make a drawing for initial case and final case, are you given directions?

- Astrophysics

Anyways to find the angle of the motion we use \[\tan \theta = \left( \frac{ |P_y f| }{ |P_x f| } \right)\]

- anonymous

I wasn't given any specific directions, all I wrote was all that was there...
Ah, alright, so it'll be
tan(theta) = (2.40 x 10^4 (f) / 7.00 x 10^4 (f))?

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## More answers

- Astrophysics

The f here just means final case, but yes, that's fine \[\tan \theta = \left( \frac{ 2.4 }{ 7 } \right)\]

- Astrophysics

Do you know how to isolate angle theta?

- Astrophysics

By the way the reason I used 2.4 and 7 and did not include 10^4 because 10^4/10^4 is just 1.

- anonymous

theta^-1 right?

- Astrophysics

Right, we take the inverse! :)

- anonymous

Oh wait...would it look something like this?
(theta) = tan^-1= (2.4/7)

- Astrophysics

\[\theta = \tan ^{-1} \left( \frac{ 2.4 }{ 7 } \right)\]

- Astrophysics

|dw:1434948081957:dw|

- Astrophysics

What did you get for the angle?

- anonymous

Do I divide the 2.4 and 7 before doing so? Because I did, getting 0.34 and the final angle: 18.8 degrees

- Astrophysics

That's fine, but don't round numbers until the final answer, you should get 18.92...degrees

- anonymous

Ah, okay! And here one of the answers is 18.9 degrees, guess we got it. :)
Thanks once again! ^ ^

- Astrophysics

Np!

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