A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
.
anonymous
 one year ago
.

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i would factor it, then make a table hen graph iy

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0almost.... you need to factor more

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0ok... you have a perfect square in the form of \[(a^2b^2) = (a+b)(ab) \]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0\[(x^24) \] is a perfect square.. what is the square root of x^2 and what is the square root of 4

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0a perfect square is the product of a rational number multiplied by itself. the product of a polynomial multiplied by itself.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0A perfect square is a number that can be expressed as the product of two equal integers.

Zale101
 one year ago
Best ResponseYou've already chosen the best response.0a is squared and so does x b is squared but 4 is the square of what number?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0\[f(x) = x^3 + 4x^2  x  4\] factor by grouping which you did and that's fine you got to \[(x^24)(x+1) \] but you need to factor more..

Zale101
 one year ago
Best ResponseYou've already chosen the best response.0\(\Large (a^2b^2)=(a+b)(ab)\) \(\Large (x^24)=(x^22^2)\) clear?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0something's wrong here.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0factor my grouping (at least when I did it) had something else as a perfect square

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0\[f(x) = x^3 + 4x^2  x  4 \rightarrow x^2(x+4)1(x+4)\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0you shouldn't rearrange the terms.. _ that's why you had a different answer.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0second line is where everything got messed up x^3+x4x^24 x(x^2+1)4(x^2+1) you have an imaginary number case

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0Leave the function alone! *FIRST STEP* Second step use factor by grouping (two pairs!) first and second term has a common factor.. third and fourth term has a common factor

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0\[f(x) = x^3 + 4x^2  x  4 \] look at the first two terms.. what do they have in common?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0ok .. we have four terms x^3 < 1st term 4x^2  2nd term x < 3rd term 4 <  4th term focus on the first and second only what do they have in common?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0yes... how many x's though?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0\[x^34x^2 => (x)(x)(x)4(x)(x) \]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0how many x's can I take out?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0WHAT! I have three x's and I have 2 x's

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0x4 now what can I take out? =_=

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0what can I yank out to make sure I have (x+4) ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0I have x4 I want x+4 what do I need to yank out?
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.