.

- anonymous

.

- chestercat

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- anonymous

i would factor it, then make a table hen graph iy

- UsukiDoll

almost.... you need to factor more

- UsukiDoll

ok... you have a perfect square in the form of \[(a^2-b^2) = (a+b)(a-b) \]

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## More answers

- UsukiDoll

\[(x^2-4) \] is a perfect square..
what is the square root of x^2 and what is the square root of 4

- UsukiDoll

no.

- Zale101

|dw:1434948176809:dw|

- UsukiDoll

a perfect square is
the product of a rational number multiplied by itself.
the product of a polynomial multiplied by itself.

- UsukiDoll

A perfect square is a number that can be expressed as the product of two equal integers.

- UsukiDoll

what are you doing?

- Zale101

a is squared and so does x
b is squared but 4 is the square of what number?

- UsukiDoll

\[f(x) = x^3 + 4x^2 - x - 4\]
factor by grouping which you did and that's fine
you got to \[(x^2-4)(x+1) \]
but you need to factor more..

- Zale101

\(\Large (a^2-b^2)=(a+b)(a-b)\)
\(\Large (x^2-4)=(x^2-2^2)\)
clear?

- UsukiDoll

something's wrong here.

- UsukiDoll

factor my grouping (at least when I did it) had something else as a perfect square

- UsukiDoll

\[f(x) = x^3 + 4x^2 - x - 4 \rightarrow x^2(x+4)-1(x+4)\]

- UsukiDoll

\[(x+4)(x^2-1) \]

- UsukiDoll

you shouldn't rearrange the terms.. -_- that's why you had a different answer.

- UsukiDoll

second line is where everything got messed up
x^3+x-4x^2-4
x(x^2+1)-4(x^2+1)
you have an imaginary number case

- UsukiDoll

Leave the function alone! *FIRST STEP*
Second step use factor by grouping (two pairs!)
first and second term has a common factor.. third and fourth term has a common factor

- UsukiDoll

\[f(x) = x^3 + 4x^2 - x - 4 \]
look at the first two terms.. what do they have in common?

- UsukiDoll

ok .. we have four terms
x^3 <- 1st term
4x^2 - 2nd term
-x <- 3rd term
-4 < - 4th term
focus on the first and second only what do they have in common?

- UsukiDoll

yes... how many x's though?

- UsukiDoll

\[x^3-4x^2 => (x)(x)(x)-4(x)(x) \]

- UsukiDoll

how many x's can I take out?

- UsukiDoll

WHAT! I have three x's and I have 2 x's

- UsukiDoll

-x-4
now what can I take out?
=_=

- UsukiDoll

what can I yank out to make sure I have (x+4) ?

- UsukiDoll

I have -x-4
I want x+4
what do I need to yank out?

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