The vertex of this parabola is at (-3, -1). When the y-value is 0, the x-value is 4. What is the coefficient of the squared term in the parabola's equation?

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The vertex of this parabola is at (-3, -1). When the y-value is 0, the x-value is 4. What is the coefficient of the squared term in the parabola's equation?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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help me please
Apparently, you have 2 given points the vertex and the x-intercept the vertex is (-3,-1) the x-intercept is (4,0) clear?
no

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Other answers:

i dont understand any
what part of what i just said didn't make sense to you?
well i dont understand how to get the answer
i know you dont understand on how to find the answer, but what about the description i made, did it make sense ?
yes
The equation of a parabola in a vertex form \[y = a(x - h)^2 + k\] vertex (h,k)=(-3,-1) x intercept x,y=(4,0) tat means the only variable left is a, solve for it
Sorry about the confusion earlier, i should have used y=a(x-h)^2+k since you already mentioned it to me.
Here is a summary of the 3 main points
So you are given 2 points, and one of them is the vertex, at the vertex f'(x) = 0 f ' (-3)=0 (1) f(-3) =1 (2) f(4)=0 (3) So you have these 3 pieces of information
A parabola is a quadratic of the form y=ax^2+bx+c you have 3 unknowns and you can form 3 linearly independent equations y'(-3)=0 y(-3)=1 y(4)=0 solve for a,b,c
that 1 should be -1, fix that and carry on

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