At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
first, can you tell me what the centre is for each of them?
To find the centre, use : centre of circle is at (h,k) equation:(x−h)2+(y−k)2=r2 So for e.g... for the first one A. \[(x+2)^2 + (y - 5)^2 = 9 \rightarrow centre (-2, 5) \]
wait why did the 2 turn negative
because our general equation is this: \[(x-h)^2 + (y -k)^2 = r^2 , centre (h, k)\]
So when we compare it to: \[(x+2)^2 + (y - 5)^2 = 9, centre (-2, 5) \]
is that right?
OKaaayyy let's seee :) A. centre (-2, 5) B. centre (4, -3) C. centre (5, 6) D. centre (-1, 7)
excellent work :)!
thank you :)
d and a are the answers
they lie in the second quadrant
no problem :) That's correct :D Wonderful!
thank you for your help!
you're welcome ^_^!
The circle below is centered at the point (-2, 1), and has a radius of length 3. What is its equation? http://media.apexlearning.com/Images/200707/01/7f8d2e18-9709-467b-9bc7-1dc4df8eb1a9.gif A. (x + 2)2 + (y - 1)2 = 9 B. (x - 2)2 + (y + 1)2 = 3 C. (x + 1)2 + (y - 2)2 = 9 D. (x - 1)2 + (y + 2)2 = 3
when it asks for whats its equation, does it mean to fully work out the equation or just set it up?
Remember that the STANDARD equation of a circle is: \[(x-h)^2 + (y-k)^2 = r^2 \] where centre is at (h, k) So since they've told us that centre is at (-2, 1) , you want to find the equation. They've also told you that radius (r) =3 So now we know h = -2, k = 1 , r = 3 so sub this into the standard equation of a circle :)
it would be (x+2)^2(x-1)^2=3^2
yess :D That's correct
thank you :)
you're welcome :D!