Which of the following circles have their centers in the second quadrant? Check all that apply.
A. (x + 2)2 + (y - 5)2 = 9
B. (x - 4)2 + (y + 3)2 = 32
C. (x - 5)2 + (y - 6)2 = 25
D. (x + 1)2 + (y - 7)2 = 16
Stacey Warren - Expert brainly.com
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first, can you tell me what the centre is for each of them?
To find the centre, use :
centre of circle is at (h,k)
So for e.g... for the first one A.
\[(x+2)^2 + (y - 5)^2 = 9 \rightarrow centre (-2, 5) \]
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because our general equation is this:
\[(x-h)^2 + (y -k)^2 = r^2 , centre (h, k)\]
So when we compare it to:
\[(x+2)^2 + (y - 5)^2 = 9, centre (-2, 5) \]
is that right?
OKaaayyy let's seee :)
A. centre (-2, 5)
B. centre (4, -3)
C. centre (5, 6)
D. centre (-1, 7)
excellent work :)!
thank you :)
d and a are the answers
they lie in the second quadrant
no problem :)
That's correct :D Wonderful!
thank you for your help!
you're welcome ^_^!
The circle below is centered at the point (-2, 1), and has a radius of length 3. What is its equation?
A. (x + 2)2 + (y - 1)2 = 9
B. (x - 2)2 + (y + 1)2 = 3
C. (x + 1)2 + (y - 2)2 = 9
D. (x - 1)2 + (y + 2)2 = 3
when it asks for whats its equation, does it mean to fully work out the equation or just set it up?
Remember that the STANDARD equation of a circle is:
\[(x-h)^2 + (y-k)^2 = r^2 \] where centre is at (h, k)
So since they've told us that centre is at (-2, 1) , you want to find the equation.
They've also told you that radius (r) =3
So now we know h = -2, k = 1 , r = 3 so sub this into the standard equation of a circle :)